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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

301 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 251–260 of 301
Topics in JEE Physics
Q.251 Easy Thermodynamics
A heat pump delivers 5000 J of heat to a house while consuming 1500 J of work. Its coefficient of performance is:
A 3.33
B 2.33
C 4.33
D 1.33
Correct Answer:  A. 3.33
EXPLANATION

For heat pump: COP = Q_h/W = 5000/1500 = 3.33. This indicates the pump delivers 3.33 J of heat for every 1 J of work input.

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Q.252 Easy Thermodynamics
What is the efficiency of a Carnot engine operating between 400 K and 300 K?
A 25%
B 33.3%
C 50%
D 75%
Correct Answer:  A. 25%
EXPLANATION

Carnot efficiency: η = 1 − (T_cold/T_hot) = 1 − (300/400) = 1 − 0.75 = 0.25 = 25%

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Q.253 Easy Thermodynamics
An ideal gas undergoes an adiabatic process. If the gas is compressed, which of the following is true?
A Temperature decreases, internal energy decreases
B Temperature increases, internal energy increases
C Temperature remains constant, internal energy increases
D Temperature decreases, internal energy remains constant
Correct Answer:  B. Temperature increases, internal energy increases
EXPLANATION

In adiabatic compression (Q = 0), work is done on the gas (W < 0). By first law: ΔU = Q − W = 0 − W > 0. Since ΔU ∝ ΔT for ideal gas, temperature increases.

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Q.254 Easy Thermodynamics
A system absorbs 500 J of heat and performs 200 J of work on the surroundings. What is the change in internal energy of the system?
A 300 J
B 700 J
C −300 J
D −700 J
Correct Answer:  A. 300 J
EXPLANATION

By first law of thermodynamics: ΔU = Q − W = 500 − 200 = 300 J

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Q.255 Easy Thermodynamics
A carnot engine operates between temperatures 500 K and 300 K. What is its maximum efficiency?
A 40%
B 60%
C 83.3%
D 16.7%
Correct Answer:  A. 40%
EXPLANATION

Carnot efficiency: η = 1 - (Tc/Th) = 1 - (300/500) = 1 - 0.6 = 0.4 = 40%

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Q.256 Easy Thermodynamics
In an adiabatic process, if a gas is compressed, which statement is correct?
A Temperature decreases
B Temperature increases
C Temperature remains constant
D Heat is absorbed from surroundings
Correct Answer:  B. Temperature increases
EXPLANATION

In adiabatic compression, no heat exchange occurs (Q=0). Work is done on the gas, so ΔU = W (positive). Since ΔU increases, temperature must increase.

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Q.257 Easy Thermodynamics
For one mole of an ideal monatomic gas, the ratio Cp/Cv is:
A 1.40
B 1.67
C 1.33
D 1.50
Correct Answer:  B. 1.67
EXPLANATION

For monatomic gas: Cv = (3/2)R and Cp = (5/2)R. Therefore Cp/Cv = (5/2)/(3/2) = 5/3 ≈ 1.67

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Q.258 Easy Thermodynamics
A thermodynamic system undergoes a process where internal energy increases by 150 J while the system does 100 J of work on surroundings. What is the heat absorbed by the system?
A 250 J
B 50 J
C -50 J
D 150 J
Correct Answer:  A. 250 J
EXPLANATION

By first law: ΔU = Q - W. Here ΔU = 150 J, W = 100 J (work done by system). So Q = ΔU + W = 150 + 100 = 250 J

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Q.259 Easy Thermodynamics
For a diatomic ideal gas at room temperature, what is the ratio γ = Cₚ/Cᵥ?
A γ = 1.40
B γ = 1.67
C γ = 1.33
D γ = 1.50
Correct Answer:  A. γ = 1.40
EXPLANATION

For diatomic gas: Cᵥ = (5/2)R and Cₚ = (7/2)R. γ = Cₚ/Cᵥ = 7/5 = 1.40

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Q.260 Easy Thermodynamics
What is the Clausius statement of the second law of thermodynamics?
A Heat cannot spontaneously flow from a colder body to a hotter body without external work
B Entropy of an isolated system always increases
C No heat engine can be 100% efficient
D Internal energy is a state function
Correct Answer:  A. Heat cannot spontaneously flow from a colder body to a hotter body without external work
EXPLANATION

Clausius statement: Heat cannot spontaneously transfer from a colder body to a hotter body without external work being done on the system

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