Home Subjects JEE Physics

JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

301 Q 9 Topics Take Test
Advertisement
Difficulty: All Easy Medium Hard 281–290 of 301
Topics in JEE Physics
Q.281 Easy Mechanics
A force of 10 N acts on a mass for 5 seconds, changing its momentum by:
A 2 kg·m/s
B 15 kg·m/s
C 50 kg·m/s
D 2.5 kg·m/s
Correct Answer:  C. 50 kg·m/s
EXPLANATION

By impulse-momentum theorem, Δp = F·Δt = 10 × 5 = 50 kg·m/s

Test
Q.282 Easy Mechanics
A projectile is launched at 45° with initial velocity 20 m/s. Taking g = 10 m/s², the range is:
A 20 m
B 40 m
C 60 m
D 80 m
Correct Answer:  B. 40 m
EXPLANATION

Range = u²sin(2θ)/g = (400 × sin(90°))/10 = 400/10 = 40 m

Test
Q.283 Easy Mechanics
A stone is dropped from height h. If air resistance is ignored, what fraction of its total energy is kinetic at height h/2?
A 1/4
B 1/2
C 3/4
D 1
Correct Answer:  B. 1/2
EXPLANATION

At h/2, PE = mg(h/2), Total energy = mgh. KE = mgh - mg(h/2) = mg(h/2). Fraction = (h/2)/h = 1/2

Test
Q.284 Easy Mechanics
Two objects of equal mass collide elastically and exchange velocities. This is possible only if:
A One object was at rest before collision
B Both objects move with same velocity
C The collision is head-on
D Objects have different shapes
Correct Answer:  A. One object was at rest before collision
EXPLANATION

In elastic collision between equal masses, if one is at rest, they exchange velocities completely. This satisfies both momentum and energy conservation.

Test
Q.285 Easy Mechanics
The coefficient of static friction between a block and surface is 0.5. The maximum angle of incline at which the block remains stationary is approximately:
A 26.6°
B 30°
C 45°
D 60°
Correct Answer:  A. 26.6°
EXPLANATION

At maximum angle, tan(θ) = μs = 0.5, so θ = tan⁻¹(0.5) ≈ 26.6°

Test
Q.286 Easy Mechanics
A car of mass 1000 kg moving at 20 m/s applies brakes with deceleration of 5 m/s². What is the stopping distance?
A 40 m
B 80 m
C 120 m
D 160 m
Correct Answer:  A. 40 m
EXPLANATION

Using v² = u² - 2as, where v = 0, u = 20 m/s, a = 5 m/s². Therefore, s = u²/(2a) = 400/10 = 40 m

Test
Q.287 Easy Mechanics
A body of mass 5 kg moves with velocity 4 m/s. A force acts on it for 2 seconds and velocity becomes 10 m/s. What is the impulse?
A 20 N·s
B 30 N·s
C 40 N·s
D 50 N·s
Correct Answer:  B. 30 N·s
EXPLANATION

Impulse = Δ(momentum) = m(v₂ - v₁) = 5(10 - 4) = 30 N·s

Test
Q.288 Easy Mechanics
Three blocks of masses m, 2m, and 3m are placed on a horizontal surface. A horizontal force F is applied to the first block. What is the acceleration of the system?
A F/6m
B F/3m
C F/2m
D F/m
Correct Answer:  A. F/6m
EXPLANATION

Total mass = m + 2m + 3m = 6m. Using F = Ma: a = F/(6m)

Test
Q.289 Easy Mechanics
A rotating disc has angular velocity 10 rad/s. A point at distance 0.2 m from center has linear velocity of:
A 0.02 m/s
B 0.2 m/s
C 2 m/s
D 20 m/s
Correct Answer:  C. 2 m/s
EXPLANATION

v = ωr = 10 × 0.2 = 2 m/s

Test
Q.290 Easy Mechanics
A pulley system lifts a mass of 100 kg with an efficiency of 80%. If work output is 8000 J, what is work input?
A 8000 J
B 9000 J
C 10000 J
D 12000 J
Correct Answer:  C. 10000 J
EXPLANATION

Efficiency = (Work output/Work input) × 100. 80 = (8000/W) × 100 → W = 10000 J

Test
IGET
IGET AI
Online · Exam prep assistant
Hi! 👋 I'm your iget AI assistant.

Ask me anything about exam prep, MCQ solutions, study tips, or strategies! 🎯
UPSC strategy SSC CGL syllabus Improve aptitude NEET Biology tips