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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

434 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 91–100 of 434
Topics in JEE Physics
Q.91 Medium Semiconductors
At thermal equilibrium in a semiconductor, the product of electron and hole concentrations is:
A Equal to doping concentration
B ni² (intrinsic carrier concentration squared)
C Independent of temperature
D Dependent on applied voltage
Correct Answer:  B. ni² (intrinsic carrier concentration squared)
EXPLANATION

The mass action law states ne·nh = ni² at thermal equilibrium, regardless of doping type. This is a fundamental relationship derived from Fermi-Dirac statistics.

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Q.92 Medium Semiconductors
Zener breakdown in a semiconductor occurs when:
A Reverse bias exceeds critical value causing avalanche ionization
B Strong electric field causes direct valence band-to-conduction band tunneling
C Junction temperature exceeds Curie temperature
D Doping concentration exceeds intrinsic carrier concentration
Correct Answer:  B. Strong electric field causes direct valence band-to-conduction band tunneling
EXPLANATION

Zener breakdown involves quantum mechanical tunneling of electrons directly from valence band to conduction band under strong reverse electric field. It occurs in heavily doped junctions at lower voltages than avalanche breakdown.

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Q.93 Medium Semiconductors
The reverse saturation current in a p-n junction diode depends on:
A Applied reverse voltage
B Intrinsic carrier concentration and diffusion coefficient
C Only the doping concentration
D Temperature and forward bias voltage
Correct Answer:  B. Intrinsic carrier concentration and diffusion coefficient
EXPLANATION

Reverse saturation current I0 is determined by intrinsic carrier concentration (ni), diffusion coefficient (D), and junction properties. It is independent of reverse voltage but depends strongly on temperature.

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Q.94 Medium Semiconductors
In forward biasing of a p-n junction, the depletion region width:
A Increases
B Decreases
C Remains constant
D First increases then decreases
Correct Answer:  B. Decreases
EXPLANATION

Forward bias reduces the potential barrier at the junction, allowing carriers to move across more easily. This reduces the depletion region width, which is inversely related to the applied voltage.

Test
Q.95 Medium Semiconductors
The intrinsic carrier concentration ni in a semiconductor is given by: ni = √(NcNv)exp(-Eg/2kT). What does Nc represent?
A Number of acceptors
B Effective density of states in conduction band
C Number of donors
D Concentration of intrinsic carriers
Correct Answer:  B. Effective density of states in conduction band
EXPLANATION

Nc is the effective density of states in the conduction band, which depends on the effective mass of electrons and temperature. Similarly, Nv is for the valence band.

Test
Q.96 Medium Semiconductors
The conductivity of a semiconductor increases with temperature because:
A Resistance decreases exponentially
B More charge carriers are thermally generated
C Mobility of charge carriers increases
D Both (b) and (c) are correct, but (b) dominates
Correct Answer:  D. Both (b) and (c) are correct, but (b) dominates
EXPLANATION

While mobility decreases with temperature due to increased phonon scattering, the exponential increase in intrinsic carrier concentration dominates, resulting in net increase in conductivity. However, (b) is the primary reason.

Test
Q.97 Medium Semiconductors
In an n-type semiconductor, the Fermi level lies:
A Exactly in the middle of the bandgap
B Closer to the conduction band
C Closer to the valence band
D At the conduction band edge
Correct Answer:  B. Closer to the conduction band
EXPLANATION

In n-type semiconductors, donor levels introduce electrons near the conduction band, shifting the Fermi level upward, making it closer to the conduction band than to the valence band.

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Q.98 Medium Modern Physics
A photon of wavelength 100 pm strikes a stationary free electron. After Compton scattering at an angle of 60°, the wavelength of the scattered photon is found to be 102.4 pm. What is the kinetic energy of the recoil electron? (Given: h = 6.63 × 10⁻³⁴ J·s, c = 3 × 10⁸ m/s, mₑ = 9.1 × 10⁻³¹ kg)
A 1.65 keV
B 2.43 keV
C 3.21 keV
D 0.98 keV
Correct Answer:  A. 1.65 keV
EXPLANATION

Using Compton scattering formula: λ' - λ = (h/mₑc)(1 - cos θ). With given values, the wavelength shift is 2.4 pm. Using energy conservation, the incident photon energy is E₀ = hc/λ ≈ 12.4 keV. The scattered photon energy E' = hc/λ' ≈ 12.1 keV. The kinetic energy of electron = E₀ - E' ≈ 1.65 keV.

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Q.99 Medium Modern Physics
The intensity of characteristic X-rays depends on:
A Only the atomic number of the target material
B Only the kinetic energy of incident electrons
C Both atomic number and electron beam current
D The frequency of X-rays only
Correct Answer:  C. Both atomic number and electron beam current
EXPLANATION

Characteristic X-ray intensity depends on the number of inner-shell electrons available (atomic number) and the number of incident electrons (beam current).

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Q.100 Medium Modern Physics
According to the uncertainty principle, if the position of an electron is known with uncertainty Δx = 10⁻¹⁰ m, the minimum uncertainty in momentum is:
A 5.27 × 10⁻²⁵ kg·m/s
B 1.055 × 10⁻²⁴ kg·m/s
C 3.16 × 10⁻²⁴ kg·m/s
D 2.64 × 10⁻²⁵ kg·m/s
Correct Answer:  A. 5.27 × 10⁻²⁵ kg·m/s
EXPLANATION

Δx·Δp ≥ h/(4π). Δp ≥ 1.055×10⁻³⁴/(4π×10⁻¹⁰) ≈ 5.27 × 10⁻²⁵ kg·m/s.

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