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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

434 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 211–220 of 434
Topics in JEE Physics
Q.211 Medium Magnetism
A paramagnetic material placed in a magnetic field becomes magnetized. This is because:
A Unpaired electrons align with the field
B Electrons stop orbiting nuclei
C All electrons pair up
D Nuclear spins align
Correct Answer:  A. Unpaired electrons align with the field
EXPLANATION

In paramagnetic materials, unpaired electrons have permanent magnetic moments that align with external field

Test
Q.212 Medium Magnetism
When a conductor moves through a magnetic field, an EMF is induced. This is due to the Lorentz force on:
A Free electrons in the conductor
B Fixed ions in the conductor
C Nucleus of atoms
D Lattice vibrations
Correct Answer:  A. Free electrons in the conductor
EXPLANATION

Motional EMF arises because free electrons experience Lorentz force F = -e(v × B) as conductor moves through field

Test
Q.213 Medium Magnetism
An electron (charge -e) and a proton (charge +e) move perpendicular to the same uniform magnetic field with the same velocity. The ratio of their radii of curvature is:
A 1:1
B m_e/m_p
C m_p/m_e
D e/(2e) = 1/2
Correct Answer:  B. m_e/m_p
EXPLANATION

r = mv/(eB), so r_e/r_p = (m_e/m_p) = 1/1836 approximately

Test
Q.214 Medium Magnetism
The mutual inductance between two coils depends on:
A Only the geometry and relative orientation of coils
B Only the currents in the coils
C Only the resistances of coils
D The distance between coils and their currents
Correct Answer:  A. Only the geometry and relative orientation of coils
EXPLANATION

Mutual inductance M₁₂ = k√(L₁L₂) depends on coil geometry, orientation, and proximity, not on current or resistance

Test
Q.215 Medium Magnetism
A bar magnet is cut into two equal halves perpendicular to its length. The magnetic moment of each half is:
A M/2
B M
C 2M
D M/4
Correct Answer:  A. M/2
EXPLANATION

When cut perpendicular to length, magnetic moment is halved. Each piece has half the pole strength or length.

Test
Q.216 Medium Magnetism
A conducting rod of mass m slides on two parallel rails separated by distance d in a magnetic field B perpendicular to the plane. If the rod moves with constant velocity v, the magnetic force on it is:
A F = Bvd
B F = B²d²v/R
C F = Bdv
D F = B²vd²
Correct Answer:  B. F = B²d²v/R
EXPLANATION

Induced EMF: ε = Bdv, induced current: I = Bdv/R, magnetic force: F = BId = B²d²v/R (opposes motion)

Test
Q.217 Medium Magnetism
A solenoid of length L and cross-sectional area A has N turns. Its self-inductance is:
A L = μ₀N²A/L
B L = μ₀NA²/L
C L = μ₀N/AL
D L = μ₀L/N²A
Correct Answer:  A. L = μ₀N²A/L
EXPLANATION

Self-inductance of solenoid: L = μ₀n²V = μ₀(N/L)²AL = μ₀N²A/L

Test
Q.218 Medium Magnetism
A rectangular coil of area A and N turns is rotated in a uniform magnetic field B with angular velocity ω. The maximum induced EMF is:
A ε = NABω
B ε = NBω
C ε = NAB/ω
D ε = AB/Nω
Correct Answer:  A. ε = NABω
EXPLANATION

Maximum EMF in rotating coil: ε_max = NABω, where Φ = NBA cos(ωt), so ε = dΦ/dt = NABω sin(ωt)

Test
Q.219 Medium Magnetism
A rectangular conducting loop is partially inside a uniform magnetic field region. If the loop is pulled out with constant velocity v, the induced EMF depends on:
A The length of the side cutting field lines, velocity, and magnetic field strength
B Only the magnetic field strength
C Only the velocity
D The area of the loop inside the field
Correct Answer:  A. The length of the side cutting field lines, velocity, and magnetic field strength
EXPLANATION

EMF induced ε = BLv where L is the length of the conductor cutting magnetic field lines and v is the velocity. It depends on all three factors: B, L, and v.

Test
Q.220 Medium Magnetism
In a cyclotron, a charged particle spirals outward as it gains energy. The frequency of revolution is independent of:
A Magnetic field strength
B Particle velocity
C Particle mass
D Particle charge
Correct Answer:  B. Particle velocity
EXPLANATION

The cyclotron frequency f = qB/(2πm) is independent of velocity. As velocity increases, radius increases but period remains constant (independent of v).

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