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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

434 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 231–240 of 434
Topics in JEE Physics
Q.231 Medium Magnetism
A proton and an electron, both accelerated through the same potential difference, enter a uniform magnetic field perpendicularly. Which has a larger radius of curvature?
A Proton (due to larger mass)
B Electron (due to smaller mass)
C Both have equal radii
D Cannot be determined without knowing B
Correct Answer:  A. Proton (due to larger mass)
EXPLANATION

Both particles gain same kinetic energy, so mv²/2 is same. Since r = mv/eB and proton has much larger mass than electron, proton has larger radius of curvature.

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Q.232 Medium Magnetism
The magnetic field due to a long straight wire carrying current I at perpendicular distance r is:
A B = μ₀I/2πr
B B = μ₀I/4πr
C B = μ₀I/r
D B = μ₀I/πr²
Correct Answer:  A. B = μ₀I/2πr
EXPLANATION

Using Ampere's law for a long straight wire, ∮B·dl = μ₀I_enclosed. For a circular path of radius r: B(2πr) = μ₀I, giving B = μ₀I/2πr.

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Q.233 Medium Magnetism
The magnetic moment of an electron orbiting in the first Bohr orbit is approximately:
A 1 Bohr magneton
B 0.5 Bohr magneton
C 2 Bohr magneton
D 0.25 Bohr magneton
Correct Answer:  A. 1 Bohr magneton
EXPLANATION

The magnetic moment of an electron in the first Bohr orbit equals 1 Bohr magneton (μ_B = eℏ/2m_e ≈ 9.27 × 10⁻²⁴ J/T). This is a fundamental quantum result.

Test
Q.234 Medium Magnetism
A rectangular loop of dimensions a × b carrying current I is placed in a uniform magnetic field B. The maximum torque on the loop is:
A τ = BIab
B τ = BIa/b
C τ = BI/ab
D τ = BIa²b
Correct Answer:  A. τ = BIab
EXPLANATION

Torque on a current loop in a magnetic field is τ = NIAB sin(θ), where A is the area and θ is the angle. Maximum torque occurs when sin(θ) = 1, giving τ_max = BIab for N=1.

Test
Q.235 Medium Magnetism
Two parallel wires carrying currents I₁ and I₂ in opposite directions are separated by distance d. The force between them is:
A Repulsive with magnitude F = μ₀I₁I₂d/2πℓ
B Attractive with magnitude F = μ₀I₁I₂/2πdℓ
C Repulsive with magnitude F = μ₀I₁I₂/2πdℓ
D Attractive with magnitude F = μ₀I₁I₂d/2πℓ
Correct Answer:  C. Repulsive with magnitude F = μ₀I₁I₂/2πdℓ
EXPLANATION

Currents in opposite directions repel each other. The force per unit length is F/ℓ = μ₀I₁I₂/2πd, making total force F = μ₀I₁I₂ℓ/2πd (repulsive).

Test
Q.236 Medium Magnetism
An electron enters a region of uniform magnetic field with velocity v perpendicular to the field. If the magnetic field strength is B, the radius of curvature is:
A r = mv/eB
B r = eB/mv
C r = m/eBv
D r = eBv/m
Correct Answer:  A. r = mv/eB
EXPLANATION

For a charged particle in a magnetic field, centripetal force equals magnetic force: mv²/r = evB, giving r = mv/eB. This is the radius of the circular path.

Test
Q.237 Medium Current Electricity
A heating element rated 1000W, 220V is connected to a 110V supply. The heat produced becomes:
A 250W
B 500W
C 1000W
D 2000W
Correct Answer:  A. 250W
EXPLANATION

Resistance of element R = V²/P = 220²/1000 = 48.4Ω (constant). At 110V: P' = V'²/R = 110²/48.4 ≈ 250W. Power varies with square of voltage.

Test
Q.238 Medium Current Electricity
A wire of length L and cross-sectional area A has resistance R. If the wire is stretched to 1.5 times its original length without change in volume, what will be its new resistance?
A 2.25R
B 1.5R
C 3.375R
D 0.667R
Correct Answer:  A. 2.25R
EXPLANATION

When stretched, length becomes 1.5L. Volume remains constant (LA = A'L'), so A' = A/1.5. New resistance R' = ρ(1.5L)/(A/1.5) = 2.25ρL/A = 2.25R

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Q.239 Medium Current Electricity
In Joule heating, if voltage is doubled and resistance is halved, the power dissipated becomes:
A 2 times
B 4 times
C 8 times
D 16 times
Correct Answer:  C. 8 times
EXPLANATION

P = V²/R. New P = (2V)²/(R/2) = 4V²×2/R = 8(V²/R) = 8P₀

Test
Q.240 Medium Current Electricity
Which of the following shows non-ohmic behavior?
A Copper wire at constant temperature
B Carbon resistor
C Tungsten filament bulb
D Constantan wire
Correct Answer:  C. Tungsten filament bulb
EXPLANATION

Tungsten filament's resistance increases significantly with temperature due to heating, causing non-linear I-V characteristic (non-ohmic).

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