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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

434 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 361–370 of 434
Topics in JEE Physics
Q.361 Medium Thermodynamics
A heat engine absorbs 1000 J from a hot reservoir and rejects 600 J to a cold reservoir in one cycle. Its efficiency is:
A 40%
B 60%
C 37.5%
D 66.7%
Correct Answer:  A. 40%
EXPLANATION

Efficiency η = W/Q_h = (Q_h − Q_c)/Q_h = (1000 − 600)/1000 = 400/1000 = 0.40 = 40%

Test
Q.362 Medium Thermodynamics
A cyclic process ABCA is shown on a P-V diagram where AB is isothermal expansion, BC is adiabatic compression, and CA is isochoric process. Which statement is correct?
A Net work done by gas is positive, net heat absorbed is positive
B Net work done by gas is negative, net heat absorbed is negative
C Net work done by gas is positive, net heat absorbed is negative
D Cannot determine without specific values
Correct Answer:  A. Net work done by gas is positive, net heat absorbed is positive
EXPLANATION

In a complete cycle returning to initial state, ΔU = 0, so Q = W. For expansion-dominated processes in a typical cycle, W > 0 and Q > 0.

Test
Q.363 Medium Thermodynamics
The molar heat capacity of a diatomic ideal gas at constant pressure is (R = 8.314 J/mol·K):
A (5/2)R
B (7/2)R
C (3/2)R
D (9/2)R
Correct Answer:  B. (7/2)R
EXPLANATION

For diatomic gas: Cv = (5/2)R, and Cp = Cv + R = (5/2)R + R = (7/2)R. This is at room temperature where vibration is not excited.

Test
Q.364 Medium Thermodynamics
A gas expands from 1 L to 5 L against a constant external pressure of 2 atm. The work done by the gas is approximately:
A 8.08 J
B 404 J
C 808 J
D 1,216 J
Correct Answer:  C. 808 J
EXPLANATION

W = P_ext × ΔV = 2 atm × (5 − 1) L = 2 × 4 = 8 atm·L = 8 × 101.325 J ≈ 810.6 J ≈ 808 J

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Q.365 Medium Thermodynamics
Two identical blocks of metal at different temperatures are brought into thermal contact in an isolated system. The process is:
A Reversible and entropy of universe increases
B Reversible and entropy of universe remains constant
C Irreversible and entropy of universe increases
D Irreversible and entropy of universe remains constant
Correct Answer:  C. Irreversible and entropy of universe increases
EXPLANATION

Heat transfer between objects at different temperatures is irreversible. For an isolated system, ΔS_universe = ΔS_system > 0 (irreversible process), not equal to zero.

Test
Q.366 Medium Thermodynamics
One mole of an ideal monoatomic gas is heated at constant volume from 300 K to 600 K. The change in internal energy is (R = 8.314 J/mol·K):
A 12,471 J
B 24,942 J
C 37,413 J
D 6,235.5 J
Correct Answer:  A. 12,471 J
EXPLANATION

For monoatomic ideal gas, Cv = (3/2)R. ΔU = nCvΔT = 1 × (3/2) × 8.314 × (600 − 300) = (3/2) × 8.314 × 300 = 3,741 × 3.33 ≈ 12,471 J

Test
Q.367 Medium Thermodynamics
A refrigerator operates on a Carnot cycle between -10°C and 30°C. The coefficient of performance (COP) is approximately:
A 4.5
B 6.5
C 8.5
D 10.5
Correct Answer:  B. 6.5
EXPLANATION

COP = Tc/(Th - Tc) = 263/(303 - 263) = 263/40 ≈ 6.575 ≈ 6.5

Test
Q.368 Medium Thermodynamics
The molar heat capacity at constant pressure for a diatomic ideal gas is:
A (3/2)R
B (5/2)R
C (7/2)R
D (9/2)R
Correct Answer:  C. (7/2)R
EXPLANATION

For diatomic gas: Cv = (5/2)R. Using Cp = Cv + R, we get Cp = (5/2)R + R = (7/2)R

Test
Q.369 Medium Thermodynamics
A cylinder with a movable piston contains 2 moles of ideal gas at 300 K and 1 atm. When heated at constant pressure to 600 K, what is the work done by the gas? (R = 8.314 J/mol·K)
A 2492 J
B 4984 J
C 9968 J
D 1246 J
Correct Answer:  B. 4984 J
EXPLANATION

For isobaric process: W = nRΔT = 2 × 8.314 × (600 - 300) = 2 × 8.314 × 300 = 4988.4 ≈ 4984 J

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Q.370 Medium Thermodynamics
Which process would result in the maximum work output from an ideal gas expansion between two fixed pressures?
A Isothermal process
B Isobaric process
C Isochoric process
D Adiabatic process
Correct Answer:  A. Isothermal process
EXPLANATION

For expansion between fixed initial and final states, isothermal process yields maximum work because the gas maintains maximum pressure throughout the expansion compared to adiabatic or other processes.

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