Govt. Exams
Maximum particle velocity = Aω = A(2πf) = 0.1 × 2π × 50 = 10π m/s
Frequency remains constant when a wave passes between media. Velocity, wavelength, and direction (refraction) change, but frequency does not
Using f' = f(v/(v-vs)), 1100 = 1000(v/(v-10)). Solving: 1.1(v-10) = v, 0.1v = 11, v = 330 m/s
Phase difference = (path difference/λ) × 2π = (1.5λ/λ) × 2π = 3π
For open pipe: L = λ/2, For closed pipe: L = λ/4. Ratio of frequencies = 2:1. New frequency = 500/2 = 250 Hz
In the nth harmonic, number of nodes excluding ends = n-1. For third harmonic, nodes = 3-1 = 2
Using Doppler effect, f' = f(v/(v-vs)) = 500(330/(330-10)) = 500(330/320) = 515.6 Hz ≈ 515 Hz
For fundamental mode, L = λ/2, so λ = 2L = 2 m. v = fλ = 100 × 2 = 200 m/s
Fringe width β = λD/d, where D is the distance to the screen and d is the slit separation
Upon reflection from a denser medium (fixed end), there is a phase change of π radians or 180°