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JEE Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

225 Q 5 Topics Take Test
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Difficulty: All Easy Medium Hard 71–80 of 225
Topics in JEE Chemistry
Q.71 Medium Electrochemistry
Which of the following has the highest reduction potential?
A F₂ + 2e⁻ → 2F⁻
B Cl₂ + 2e⁻ → 2Cl⁻
C Br₂ + 2e⁻ → 2Br⁻
D I₂ + 2e⁻ → 2I⁻
Correct Answer:  A. F₂ + 2e⁻ → 2F⁻
EXPLANATION

Fluorine has the highest reduction potential among the halogens, approximately +2.87 V. Reduction potentials decrease down the halogen group: F₂ > Cl₂ > Br₂ > I₂.

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Q.72 Medium Electrochemistry
How many grams of copper will be deposited when 2 faradays of electricity are passed through a copper sulfate solution?
A 32 g
B 64 g
C 128 g
D 256 g
Correct Answer:  C. 128 g
EXPLANATION

Cu²⁺ + 2e⁻ → Cu. For 2 faradays (2 moles of electrons), moles of Cu deposited = 2/2 = 1 mol. Mass = 1 × 64 = 64 g. Wait, let me recalculate: 2 faradays means 2 moles of e⁻. Cu²⁺ requires 2e⁻, so 2 moles of e⁻ deposits 1 mole of Cu = 64 g. The answer should be B, but checking: if 2 faradays, then 2×64/2 = 64g. Correction: Answer is 64g (option B). However, reviewing: 2F of charge produces 2 mol e⁻, which deposits 64g Cu. The listed answer C (128g) would require reconsideration - using the formula: mass = (charge × molar mass)/(n × F) = (2F × 64)/(2 × 96500) is incorrect reasoning. Correct: 2 faradays deposit 1 mole of Cu = 64g.

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Q.73 Medium Electrochemistry
In the Daniel cell, the half-cell potentials are: Cu²⁺ + 2e⁻ → Cu, E° = +0.34 V and Zn²⁺ + 2e⁻ → Zn, E° = -0.76 V. Calculate E°cell:
A 0.42 V
B 0.76 V
C 1.10 V
D 1.34 V
Correct Answer:  C. 1.10 V
EXPLANATION

E°cell = E°cathode - E°anode = 0.34 - (-0.76) = 0.34 + 0.76 = 1.10 V. Cu²⁺ is reduced (cathode) and Zn is oxidized (anode).

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Q.74 Medium Electrochemistry
The standard cell potential for a reaction is -0.5 V. What can be concluded about this reaction?
A The reaction is spontaneous under standard conditions
B The reaction is non-spontaneous under standard conditions
C ΔG° is positive
D Both B and C are correct
Correct Answer:  D. Both B and C are correct
EXPLANATION

A negative E° (E°cell < 0) indicates a non-spontaneous reaction under standard conditions. ΔG° = -nFE°, so negative E° gives positive ΔG°.

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Q.75 Medium Electrochemistry
A metal X is more easily oxidized than metal Y. If X and Y form a galvanic cell, which metal acts as the anode?
A Metal X (anode)
B Metal Y (anode)
C Depends on the electrolyte used
D Both metals act as anodes
Correct Answer:  A. Metal X (anode)
EXPLANATION

The metal that is more easily oxidized (more reactive) acts as the anode. Metal X, being more reactive, loses electrons and acts as the anode (negative electrode).

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Which of the following lanthanide elements has the electronic configuration [Xe]4f⁷5d¹6s²?
A Gadolinium (Gd)
B Europium (Eu)
C Samarium (Sm)
D Terbium (Tb)
Correct Answer:  A. Gadolinium (Gd)
EXPLANATION

Gadolinium has atomic number 64 with configuration [Xe]4f⁷5d¹6s². The half-filled 4f⁷ configuration makes Gd exceptionally stable. This is the only lanthanide with a 5d electron, making it unique among the lanthanide series.

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When a solution of potassium permanganate is diluted with water in the presence of ethanol, the purple color fades. This is because:
A MnO₄⁻ ions are oxidized by ethanol
B MnO₄⁻ ions oxidize ethanol to acetaldehyde in acidic medium
C Ethanol reduces MnO₄⁻ to colorless Mn²⁺ ions
D Water molecules compete with ethanol for permanganate ions
Correct Answer:  C. Ethanol reduces MnO₄⁻ to colorless Mn²⁺ ions
EXPLANATION

Permanganate ions (MnO₄⁻) oxidize ethanol to acetaldehyde and are themselves reduced to colorless Mn²⁺ ions (or MnO₂ depending on pH), causing the purple color to fade. This is a classic redox reaction where the oxidation state of Mn changes from +7 to +2.

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The ionization potential of beryllium is higher than boron because:
A Be has smaller atomic radius
B Be has completely filled s-orbital
C Both A and B
D Be has more protons
Correct Answer:  C. Both A and B
EXPLANATION

Be (1s² 2s²) has a filled 2s orbital which is more stable. Additionally, smaller size means electrons are closer to nucleus. Both factors increase ionization potential.

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Which of the following compounds shows maximum lattice energy?
A NaCl
B MgO
C CaO
D KCl
Correct Answer:  B. MgO
EXPLANATION

MgO has the highest lattice energy due to smallest cation (Mg²⁺) and anion (O²⁻) sizes combined with higher charges. Order: MgO > NaCl > CaO > KCl.

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The bond angle in PCl₃ molecule is approximately:
A 90°
B 101.8°
C 107.5°
D 120°
Correct Answer:  B. 101.8°
EXPLANATION

PCl₃ has trigonal pyramidal geometry due to one lone pair on P. The bond angle is reduced from 120° (ideal trigonal) to 101.8° due to lone pair repulsion.

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