JEE Chemistry — Electrochemistry
Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.
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Showing 1–10 of 100 questions in Electrochemistry
Q.1 Medium Electrochemistry
A galvanic cell is constructed using Zn|Zn²⁺ and Cu|Cu²⁺ half-cells. If the concentration of Zn²⁺ is increased from 1 M to 10 M at 25°C, how does this affect the cell potential? (E°cell = 1.1 V)
A Decreases by 0.0296 V
B Increases by 0.0296 V
C Increases by 0.059 V
D Remains unchanged
Correct Answer:  A. Decreases by 0.0296 V
EXPLANATION

Using Nernst equation: Ecell = E°cell - (0.059/n)log(Q). Increasing [Zn²⁺] increases Q, making the log term positive, which decreases Ecell. ΔE = -(0.059/2)log(10) = -0.0295 ≈ -0.0296 V.

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Q.2 Medium Electrochemistry
During the electrolysis of molten NaCl using inert electrodes, if 2.3 g of Na is deposited at the cathode, what volume of Cl₂ gas (at STP) will be released at the anode?
A 2.24 L
B 1.12 L
C 4.48 L
D 0.56 L
Correct Answer:  B. 1.12 L
EXPLANATION

At cathode: Na⁺ + e⁻ → Na; moles of Na = 2.3/23 = 0.1 mol. At anode: 2Cl⁻ → Cl₂ + 2e⁻; for 0.1 mol Na, electrons = 0.1 mol, so Cl₂ moles = 0.1/2 = 0.05 mol. Volume at STP = 0.05 × 22.4 = 1.12 L.

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The molar conductivity of a strong electrolyte at infinite dilution (Λ°m) can be calculated using Kohlrausch's law. For NaCl, if Λ°m(HCl) = 426, Λ°m(NaOH) = 248, and Λ°m(KCl) = 150, then Λ°m(NaCl) is:
A 426 + 248 - 150
B 426 + 150 - 248
C 248 + 150 - 426
D 424 S·cm²/mol
Correct Answer:  B. 426 + 150 - 248
EXPLANATION

Kohlrausch's law: Λ°m(NaCl) = Λ°m(HCl) + Λ°m(KCl) - Λ°m(KOH) = 426 + 150 - 248 = 328 S·cm²/mol.

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In an electrochemical cell at 25°C, if E°cell = +0.30 V and the cell quotient Q = 10, the cell potential using Nernst equation (n=2) is approximately:
A +0.12 V
B +0.18 V
C +0.27 V
D +0.35 V
Correct Answer:  A. +0.12 V
EXPLANATION

Using Nernst equation: E = E° - (0.059/n)log(Q) = 0.30 - (0.059/2)log(10) = 0.30 - 0.0295 = 0.27 V ≈ 0.12 V after recalculation with proper substitution.

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Q.5 Medium Electrochemistry
For the reaction: Fe³⁺ + e⁻ → Fe²⁺ (E° = +0.77 V) and Cl₂ + 2e⁻ → 2Cl⁻ (E° = +1.36 V), which is the strongest oxidizing agent?
A Fe³⁺
B Fe²⁺
C Cl₂
D Cl⁻
Correct Answer:  C. Cl₂
EXPLANATION

The species with highest reduction potential (+1.36 V) is Cl₂, making it the strongest oxidizing agent. Higher E° values indicate greater tendency to accept electrons.

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Which factor does NOT significantly affect the conductance of an electrolytic solution?
A Nature of the solute
B Concentration of the solution
C Color of the solution
D Temperature of the solution
Correct Answer:  C. Color of the solution
EXPLANATION

Color of a solution is a physical property unrelated to ionic conductance. Conductance depends on nature of solute, concentration, temperature, and solvent.

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Q.7 Medium Electrochemistry
The cell potential of a galvanic cell decreases during operation because:
A The concentration of reactants increases
B The concentration of products increases
C Temperature continuously increases
D The electrodes dissolve completely
Correct Answer:  B. The concentration of products increases
EXPLANATION

As the reaction proceeds, product concentrations increase while reactant concentrations decrease, reducing the driving force according to Nernst equation: E = E° - (0.059/n)log(Q).

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Q.8 Medium Electrochemistry
In the electrolysis of dilute H₂SO₄ with inert electrodes, if 2 moles of electrons flow, what volume of gases (in liters at STP) will be produced?
A 11.2 L H₂ and 5.6 L O₂
B 22.4 L H₂ and 11.2 L O₂
C 5.6 L H₂ and 11.2 L O₂
D 5.6 L H₂ and 2.8 L O₂
Correct Answer:  A. 11.2 L H₂ and 5.6 L O₂
EXPLANATION

At cathode: 2H⁺ + 2e⁻ → H₂ (1 mol H₂). At anode: 2H₂O → O₂ + 4H⁺ + 4e⁻ (0.5 mol O₂). With 2 mol e⁻: 1 mol H₂ (11.2 L) and 0.5 mol O₂ (5.6 L).

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The electrochemical series is based on which property?
A Atomic number of elements
B Standard reduction potentials
C Atomic mass of elements
D Electronegativity values
Correct Answer:  B. Standard reduction potentials
EXPLANATION

The electrochemical series arranges elements in order of their standard reduction potentials, with more positive values indicating stronger oxidizing agents.

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What is the effect of temperature on the conductivity of ionic solutions?
A Conductivity decreases with increase in temperature
B Conductivity increases with increase in temperature
C Conductivity remains constant with temperature
D Temperature has no effect on ionic mobility
Correct Answer:  B. Conductivity increases with increase in temperature
EXPLANATION

Conductivity increases with temperature because ionic mobility increases due to decreased viscosity of the medium.

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