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JEE Physics

Physics questions for JEE Main — Mechanics, Electrostatics, Optics, Modern Physics.

434 Q 9 Topics Take Test
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Difficulty: All Easy Medium Hard 81–90 of 434
Topics in JEE Physics
Q.81 Medium Semiconductors
The minority carrier diffusion length Ln in a semiconductor depends on which parameters?
A Only on bandgap energy Eg
B On diffusion coefficient Dn and minority carrier lifetime τn
C Only on doping concentration
D On applied external voltage only
Correct Answer:  B. On diffusion coefficient Dn and minority carrier lifetime τn
EXPLANATION

Diffusion length Ln = √(Dn·τn) where Dn is diffusion coefficient and τn is minority carrier lifetime. It represents the average distance a carrier travels before recombination.

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Q.82 Medium Semiconductors
A compound semiconductor like GaAs has a direct bandgap while Si has an indirect bandgap. Which statement about light emission is correct?
A Both emit light with equal efficiency under forward bias
B GaAs is more suitable for LEDs due to direct bandgap allowing direct recombination
C Si emits more light than GaAs due to higher Eg
D Indirect bandgap materials are better for light emission
Correct Answer:  B. GaAs is more suitable for LEDs due to direct bandgap allowing direct recombination
EXPLANATION

Direct bandgap semiconductors like GaAs allow radiative recombination (photon emission) without phonon assistance, making them ideal for LEDs and lasers.

Test
Q.83 Medium Semiconductors
In a Zener diode, the Zener breakdown occurs due to:
A Impact ionization of carriers
B Tunneling of electrons from valence band to conduction band
C Thermal generation of carriers
D Forward biasing of the junction
Correct Answer:  B. Tunneling of electrons from valence band to conduction band
EXPLANATION

Zener breakdown (sharp, reversible breakdown at lower voltages) occurs when a strong electric field in the depletion region enables direct tunneling of electrons across the narrow bandgap.

Test
Q.84 Medium Semiconductors
The reverse saturation current (I₀) in a p-n junction increases exponentially with temperature. This is primarily because:
A Thermal generation of minority carriers increases
B Depletion width decreases
C Junction capacitance increases
D Applied reverse bias increases
Correct Answer:  A. Thermal generation of minority carriers increases
EXPLANATION

I₀ ∝ ni² which increases exponentially with temperature. This thermal generation of minority carriers in the neutral regions near the junction constitutes the reverse saturation current.

Test
Q.85 Medium Semiconductors
A silicon semiconductor has ni = 1.5 × 10^10 cm^-3 at 300K. If doped with 10^16 cm^-3 donor atoms, calculate the hole concentration at thermal equilibrium.
A 1.5 × 10^10 cm^-3
B 2.25 × 10^4 cm^-3
C 10^16 cm^-3
D 1.5 × 10^26 cm^-3
Correct Answer:  B. 2.25 × 10^4 cm^-3
EXPLANATION

Using mass action law: ne·nh = ni². Since ne ≈ Nd = 10^16 cm^-3, then nh = ni²/ne = (1.5×10^10)²/10^16 = 2.25×10^4 cm^-3

Test
Q.86 Medium Semiconductors
In a reverse-biased p-n junction, the depletion width increases when:
A Forward bias voltage is increased
B Reverse bias voltage magnitude is increased
C Temperature is increased
D Doping concentration is decreased uniformly
Correct Answer:  B. Reverse bias voltage magnitude is increased
EXPLANATION

Increasing reverse bias voltage creates a stronger electric field, pushing charge carriers away from the junction and widening the depletion region according to W ∝ √V.

Test
Q.87 Medium Semiconductors
The conductivity of a semiconductor is given by σ = e(neμe + nhμh). If temperature increases from 300K to 400K, which factor primarily determines the change in conductivity?
A Increase in carrier concentration dominates
B Decrease in mobility dominates
C Both effects cancel each other
D Bandgap energy becomes zero
Correct Answer:  A. Increase in carrier concentration dominates
EXPLANATION

Though mobility decreases with temperature (T^-3/2), the exponential increase in carrier concentration (proportional to exp(-Eg/2kT)) dominates, resulting in net increase in conductivity.

Test
Q.88 Medium Semiconductors
The photo-generated current in a solar cell is proportional to:
A Incident light intensity and bandgap energy
B Incident light intensity only
C Applied reverse voltage
D Diffusion coefficient squared
Correct Answer:  B. Incident light intensity only
EXPLANATION

Photo-generated current IL is directly proportional to incident light intensity (photon flux). At open circuit, the current is independent of applied voltage; voltage dependence matters for load characteristics.

Test
Q.89 Medium Semiconductors
The Hall effect coefficient (RH) for an n-type semiconductor is:
A Positive
B Negative
C Zero
D Dependent on temperature only
Correct Answer:  B. Negative
EXPLANATION

For n-type semiconductors, charge carriers are electrons (negative), so the Hall coefficient is negative. For p-type (holes), it is positive. The sign determines carrier type.

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Q.90 Medium Semiconductors
A BJT transistor operates in saturation region when:
A Base-emitter junction is forward biased and collector-base junction is reverse biased
B Both junctions are forward biased
C Both junctions are reverse biased
D Base-emitter junction is reverse biased
Correct Answer:  B. Both junctions are forward biased
EXPLANATION

In saturation, both junctions are forward biased, allowing maximum current flow. In active region, BE is forward and CB is reverse biased. In cutoff, both are reverse biased.

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