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JEE Chemistry
Organic Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

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Difficulty: All Easy Medium Hard 51–60 of 100
Topics in JEE Chemistry
Q.51 Medium Organic Chemistry
In the bromination of toluene with Br2/FeBr3, the major product is:
A 2-bromotoluene only
B 4-bromotoluene only
C ortho and para-bromotoluene (major)
D meta-bromotoluene only
Correct Answer:  C. ortho and para-bromotoluene (major)
EXPLANATION

The methyl group (-CH3) is an alkyl group, which is an electron-donating group that activates the benzene ring and is ortho/para-directing in electrophilic aromatic substitution.

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Q.52 Medium Organic Chemistry
The rate-determining step in an E1 elimination reaction is:
A Removal of hydrogen by base
B Formation of the carbocation
C Protonation of the alkene
D Formation of the alkyl halide
Correct Answer:  B. Formation of the carbocation
EXPLANATION

E1 elimination occurs in two steps: slow carbocation formation followed by fast deprotonation. The carbocation formation is the rate-determining step.

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Q.53 Medium Organic Chemistry
Which of the following will give a positive Tollens test?
A Acetone
B Benzaldehyde
C Diethyl ketone
D tert-Butyl alcohol
Correct Answer:  B. Benzaldehyde
EXPLANATION

Tollens test detects aldehydes. Benzaldehyde contains an aldehyde group (-CHO) and will be oxidized to benzoate ion, giving a positive test (silver mirror).

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Q.54 Medium Organic Chemistry
In the addition of HBr to propene, the major product is 2-bromopropane because of:
A Le Chatelier's principle
B Markovnikov's rule
C Anti-Markovnikov addition
D Hydrogen preference
Correct Answer:  B. Markovnikov's rule
EXPLANATION

Markovnikov's rule states that in addition to unsymmetrical alkenes, the hydrogen adds to the carbon with more hydrogen atoms, and the addendum to the carbon with fewer hydrogens, forming the more stable carbocation intermediate.

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Q.55 Medium Organic Chemistry
The reactivity order of alkyl halides in SN1 reactions is:
A Primary > Secondary > Tertiary
B Tertiary > Secondary > Primary
C Secondary > Primary > Tertiary
D All are equally reactive
Correct Answer:  B. Tertiary > Secondary > Primary
EXPLANATION

SN1 proceeds through carbocation formation. Tertiary carbocations are most stable (hyperconjugation and inductive effects), followed by secondary, then primary.

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Grignard reagent (RMgX) reacts with water to give:
A R-OH and MgX2
B R-H and Mg(OH)X
C R-H and MgX2
D R-OMgX and H2
Correct Answer:  C. R-H and MgX2
EXPLANATION

Grignard reagents are strong nucleophiles and strong bases. They readily abstract a proton from water, producing an alkane (R-H) and magnesium halide salt.

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Which functional group shows a strong absorption around 1700-1750 cm⁻¹ in IR spectrum?
A Ether
B Alcohol
C Carbonyl
D Alkene
Correct Answer:  C. Carbonyl
EXPLANATION

The C=O stretch of carbonyl compounds (aldehydes, ketones, carboxylic acids, esters) appears characteristically around 1700-1750 cm⁻¹ in IR spectrum.

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In the nitration of benzene using HNO3/H2SO4, the electrophile is:
A NO3-
B NO2+
C HNO3
D H+
Correct Answer:  B. NO2+
EXPLANATION

H2SO4 protonates HNO3 to form H2NO3+, which loses water to generate the nitronium ion (NO2+), the actual electrophile in electrophilic aromatic substitution.

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The IUPAC name of the compound with structure CH3-CH(OH)-CH2-CHO is:
A 3-hydroxyhexanal
B 3-hydroxybutanal
C 2-hydroxybutanal
D 1-hydroxy-3-butanal
Correct Answer:  B. 3-hydroxybutanal
EXPLANATION

The longest carbon chain contains 4 carbons with the aldehyde group (CHO) at position 1. The hydroxyl group is at position 3, giving 3-hydroxybutanal.

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Which of the following compounds will undergo SN2 reaction most readily?
A tert-butyl chloride
B ethyl bromide
C neopentyl chloride
D isopropyl iodide
Correct Answer:  B. ethyl bromide
EXPLANATION

SN2 reaction requires easy access to the carbon bearing the leaving group. Ethyl bromide (primary alkyl halide) has minimal steric hindrance and is highly reactive in SN2 reactions.

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