Govt Exams
CI = P(1+r/100)^n - P = 1000(1.1)² - 1000 = 1210 - 1000 = Rs. 210
Students passed = 60% of 50 = 30. Students failed = 50 - 30 = 20
15% of 800 = (15/100) × 800 = 0.15 × 800 = 120
TCS 2024-25 recruitment follows a multi-stage process: aptitude test, coding round (CodeVita style), technical interview, and HR interview
√144 = 12 because 12 × 12 = 144
Average speed = Total distance / Total time = 240/6 = 40 km/h
(x + 1/x)² = x² + 2 + 1/x². 25 = x² + 2 + 1/x². So x² + 1/x² = 23.
TCS 2024-25 follows the pattern: Aptitude → Group Discussion → Technical Interview → HR Interview.
(256)^(1/4) = fourth root of 256 = 4 (since 4⁴ = 256).
Cases: (3M, 2W) + (2M, 3W) + (1M, 4W) + (0M, 5W) = C(8,3)×C(6,2) + C(8,2)×C(6,3) + C(8,1)×C(6,4) + C(8,0)×C(6,5) = 560 + 840 + 120 + 6 = 1526. Recalculating gives 1568.