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Organic Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

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Difficulty: All Easy Medium Hard 71–80 of 100
Topics in JEE Chemistry
In the Williamson ether synthesis, the reactivity order for nucleophilic substitution by alkoxide ions (RO-) follows which pattern?
A Primary > Secondary > Tertiary
B Tertiary > Secondary > Primary
C Secondary > Primary > Tertiary
D Primary ≈ Secondary ≈ Tertiary
Correct Answer:  A. Primary > Secondary > Tertiary
EXPLANATION

In Williamson ether synthesis, the alkoxide ion attacks via SN2 mechanism, which prefers primary alkyl halides due to less steric hindrance. Tertiary substrates don't react due to steric hindrance.

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Q.72 Medium Organic Chemistry
The reaction of benzene with excess Cl2 in the presence of FeCl3 followed by hydrolysis gives:
A Chlorobenzene only
B Polychlorobenzene mixture
C Benzene diol
D Phenol
Correct Answer:  B. Polychlorobenzene mixture
EXPLANATION

Chlorobenzene formed initially is more deactivated than benzene, but further chlorination can occur at ortho/para positions under excess Cl2 conditions, yielding a mixture of polychlorobenzenes.

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Q.73 Medium Organic Chemistry
Which of the following carboxylic acids is most acidic?
A CH3-COOH
B CF3-COOH
C CCl3-COOH
D CBr3-COOH
Correct Answer:  B. CF3-COOH
EXPLANATION

CF3-COOH is most acidic because fluorine is highly electronegative and strongly withdraws electron density through inductive effects, stabilizing the conjugate base carboxylate ion.

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Q.74 Medium Organic Chemistry
In the preparation of phenol from cumene (isopropylbenzene), the intermediate cumene hydroperoxide is cleaved in acidic conditions to give:
A Phenol and formaldehyde
B Phenol and acetone
C Benzene and isopropanol
D Phenol and propene
Correct Answer:  B. Phenol and acetone
EXPLANATION

The cumene hydroperoxide undergoes an acid-catalyzed rearrangement (Hock rearrangement) where the isopropyl group rearranges to give phenol and acetone as the cleavage products.

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The coupling constant (J) in 1H-NMR for vicinal coupling (3J) typically ranges from:
A 0-5 Hz
B 5-18 Hz
C 18-25 Hz
D 25-40 Hz
Correct Answer:  B. 5-18 Hz
EXPLANATION

Vicinal coupling (3J) between protons separated by 3 bonds typically has values of 6-18 Hz, with typical values around 7-8 Hz for anti-periplanar and 2-5 Hz for gauche conformations.

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Q.76 Medium Organic Chemistry
Which isomer of dimethylbenzene (xylene) will show only 2 signals in 1H-NMR?
A ortho-xylene
B meta-xylene
C para-xylene
D All show 2 signals
Correct Answer:  C. para-xylene
EXPLANATION

Para-xylene has high symmetry: all four aromatic protons are equivalent (one signal) and all six methyl protons are equivalent (one signal), giving only 2 total signals in 1H-NMR.

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In the oxidation of primary alcohols using PCC (pyridinium chlorochromate), the primary alcohol is converted to:
A Carboxylic acid
B Aldehyde
C Ketone
D Ester
Correct Answer:  B. Aldehyde
EXPLANATION

PCC is a mild oxidizing agent that oxidizes primary alcohols to aldehydes without further oxidation to carboxylic acids (unlike acidic KMnO4 or K2Cr2O7).

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Q.78 Medium Organic Chemistry
The compound 2,2-dimethyl-1-propanol when heated with concentrated H2SO4 gives the major product as:
A 2,2-dimethyl-1-propene
B 2-methylbut-2-ene
C 2-methylbut-1-ene
D No reaction occurs
Correct Answer:  B. 2-methylbut-2-ene
EXPLANATION

This is a dehydration reaction where the OH group leaves, and a rearrangement occurs via hydride shift to form the more stable tertiary carbocation, leading to 2-methylbut-2-ene (more substituted alkene, Zaitsev's rule).

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Which of the following alkyl halides will give the fastest SN2 reaction with KOH in aqueous ethanol?
A (CH3)3C-Br
B CH3-CH2-CH2-Br
C CH3-CHBr-CH3
D CH2Br-CH3
Correct Answer:  D. CH2Br-CH3
EXPLANATION

SN2 reactions proceed fastest with primary alkyl halides due to minimal steric hindrance around the carbon bearing the leaving group. CH3CH2Br (primary) > CH3CHBrCH3 (secondary) > (CH3)3CBr (tertiary).

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In the nitration of toluene, the ortho and para isomers are major products because the methyl group is:
A Electron-withdrawing and meta-directing
B Electron-donating and ortho/para-directing
C Deactivating for electrophilic aromatic substitution
D Hyperconjugative and deactivating
Correct Answer:  B. Electron-donating and ortho/para-directing
EXPLANATION

The methyl group is electron-donating through inductive and hyperconjugative effects, making the benzene ring more electron-rich. This activates the ring for EAS and directs incoming electrophiles to ortho and para positions.

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