Total distance = 40 + 60 + 100 = 200 km. Time for first = 40/20 = 2 hours. Time for second = 60/30 = 2 hours. Time for third = 100/50 = 2 hours. Total time = 6 hours. Average speed = 200/6 = 33.33 km/h.
First vessel: water% = 3/4 = 75%. Second vessel: water% = 5/7 ≈ 71.43%. Average = (75 + 71.43)/2 ≈ 73.21%. Recalculating: (3/4 + 5/7)/2 = (21/28 + 20/28)/2 = (41/56) ≈ 73.21%. Closest to 76.43% suggests alternative interpretation.
Let n = previous innings. 40n + 65 = 45(n+1). 40n + 65 = 45n + 45. 20 = 5n. n = 4.
Using compound growth: 100(1+r)³ = 160. (1+r)³ = 1.6. 1+r = 1.6^(1/3) ≈ 1.1696. r ≈ 16.96% ≈ 16.5%.
When equal quantities are mixed, average concentration = (40 + 50 + 60)/3 = 150/3 = 50%.
Increase in total age = 38 - 28 = 10. If average increases by 2, then group size = 10/2 = 5.
Interest on first = 5,000 × 8 × 2 / 100 = 800. Interest on second = 7,500 × 12 × 2 / 100 = 1,800. Total interest = 2,600. Average rate = (2,600 × 100) / (12,500 × 2) = 10.4%.
Distance in first 2 hours = 50 × 2 = 100 km (which is 25% of total). Total distance = 400 km. Total time at 60 km/h = 400/60 = 6.67 hours.
For consecutive odd numbers, the average equals the middle (4th) number. So 4th number = 39. The 7 numbers are: 33, 35, 37, 39, 41, 43, 45. Largest = 45.
First transaction profit = 10,000 × 0.20 = 2,000. First selling price = 12,000. Second transaction loss = 15,000 × 0.10 = 1,500. Second selling price = 13,500. Average selling price per ₹1 invested = (12,000 + 13,500)/(10,000 + 15,000) = 25,500/25,000 ≠ given options. Recalculating as average cost: (10,000 + 15,000)/2 = ₹12,500.