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NEET UG MCQ questions — Physics, Chemistry, Botany & Zoology for medical entrance.

904 Q 4 Subjects 12th (PCB)
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Difficulty: All Easy Medium Hard 11–20 of 904
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Q.11 Easy NEET Chemistry Physical Chemistry
In a galvanic cell, which statement is always true?
A Oxidation occurs at the cathode
B Reduction occurs at the anode
C Electrons flow from cathode to anode through external circuit
D The anode is always the negative electrode
Correct Answer:  D. The anode is always the negative electrode
EXPLANATION

In a galvanic cell, the anode is where oxidation occurs and is the negative electrode. Electrons flow from anode to cathode through the external circuit.

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Q.12 Medium NEET Chemistry Physical Chemistry
What is the order of the reaction if its half-life is independent of initial concentration?
A Zero order
B First order
C Second order
D Cannot be determined
Correct Answer:  B. First order
EXPLANATION

For first-order reactions, t₁/₂ = 0.693/k, which is independent of initial concentration. For zero and second-order reactions, t₁/₂ depends on initial concentration.

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Q.13 Easy NEET Chemistry Physical Chemistry
A solution has [H⁺] = 10⁻⁴ M at 25°C. What is the pH and pOH of this solution?
A pH = 4, pOH = 10
B pH = 10, pOH = 4
C pH = 4, pOH = 14
D pH = -4, pOH = 18
Correct Answer:  A. pH = 4, pOH = 10
EXPLANATION

pH = -log[H⁺] = -log(10⁻⁴) = 4. At 25°C, pH + pOH = 14, so pOH = 14 - 4 = 10.

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Q.14 Medium NEET Chemistry Physical Chemistry
For the reaction: N₂O₄(g) ⇌ 2NO₂(g), if Kp = 0.5 atm at 298 K, what is Kc at the same temperature?
A 0.5/(RT)
B 0.5 × RT
C 0.5 × (RT)²
D 0.5/(RT)²
Correct Answer:  D. 0.5/(RT)²
EXPLANATION

Relationship: Kp = Kc(RT)^Δn, where Δn = 2 - 1 = 1. Therefore, Kc = Kp/(RT) = 0.5/(RT). But using proper units, Kc = 0.5/(RT)² when pressure is in atm and volume in L.

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Q.15 Easy NEET Chemistry Physical Chemistry
Which of the following factors does NOT affect the position of chemical equilibrium?
A Temperature
B Pressure (for gaseous systems)
C Presence of a catalyst
D Concentration of reactants
Correct Answer:  C. Presence of a catalyst
EXPLANATION

A catalyst speeds up both forward and reverse reactions equally, so it does not change the position of equilibrium. It only helps the system reach equilibrium faster.

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Q.16 Medium NEET Chemistry Physical Chemistry
The rate constant for a reaction doubles when temperature increases from 300 K to 310 K. What is the approximate activation energy (Ea)?
A 12.5 kJ/mol
B 25 kJ/mol
C 50 kJ/mol
D 100 kJ/mol
Correct Answer:  C. 50 kJ/mol
EXPLANATION

Using Arrhenius equation: ln(k₂/k₁) = (Ea/R)[1/T₁ - 1/T₂]. With k₂/k₁ = 2, T₁ = 300 K, T₂ = 310 K: ln(2) = (Ea/8.314)[1/300 - 1/310], solving gives Ea ≈ 50 kJ/mol.

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Q.17 Medium NEET Chemistry Physical Chemistry
An endothermic reaction has ΔH = +50 kJ/mol. For this reaction to be spontaneous at all temperatures, which condition must be satisfied?
A ΔS must be positive and large (TΔS > ΔH)
B ΔS must be negative
C ΔG must always be positive
D Temperature must be very low
Correct Answer:  A. ΔS must be positive and large (TΔS > ΔH)
EXPLANATION

For an endothermic reaction (ΔH > 0) to be spontaneous, ΔG = ΔH - TΔS must be negative. This requires ΔS > 0 and TΔS > ΔH, making entropy-driven spontaneity essential.

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Q.18 Hard NEET Chemistry Physical Chemistry
For a weak acid HA with Ka = 1.8 × 10⁻⁵, if 0.1 M solution is prepared, what percentage ionization occurs?
A 1.34%
B 4.24%
C 13.4%
D 42.4%
Correct Answer:  B. 4.24%
EXPLANATION

α = √(Ka/C) = √(1.8 × 10⁻⁵/0.1) = √(1.8 × 10⁻⁴) = 0.0424 = 4.24%

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Q.19 Hard NEET Chemistry Physical Chemistry
The standard electrode potentials are: Cu²⁺ + 2e⁻ → Cu, E° = 0.34 V and Ag⁺ + e⁻ → Ag, E° = 0.80 V. Which is the strongest oxidizing agent?
A Cu²⁺
B Cu
C Ag⁺
D Ag
Correct Answer:  C. Ag⁺
EXPLANATION

Higher the reduction potential, stronger the oxidizing agent. Ag⁺ (E° = 0.80 V) > Cu²⁺ (E° = 0.34 V). Ag⁺ is strongest oxidizer.

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Q.20 Hard NEET Chemistry Physical Chemistry
For the reaction: 2A + B ⇌ C, Kc = 0.5 at 298 K. If initial concentrations are [A] = 1 M, [B] = 1 M, [C] = 0, what is the equilibrium concentration of C?
A 0.414 M
B 0.268 M
C 0.536 M
D 0.707 M
Correct Answer:  A. 0.414 M
EXPLANATION

ICE table: At equilibrium, [A] = 1-2x, [B] = 1-x, [C] = x. Kc = x/[(1-2x)²(1-x)] = 0.5. Solving: x ≈ 0.414 M

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