17600 = P(1 + (11 × 4)/100); 17600 = P(1.44); P = 12222.22 ≈ 12000 (approx)
SI = (20000 × 8 × 5)/100 = 8000. Amount = 20000 + 8000 = 28000
Let sum = P. Difference in SI = (P × 12 × 3)/100 - (P × 10 × 3)/100 = (6P)/100 = 600; P = 10000
Amount = P + (P × R × T)/100; 9200 = P + (P × 8 × 4)/100; 9200 = P(1 + 0.32); P = 7000
SI = (5000 × 12 × 2.5)/100 = 1500. Amount = 5000 + 1500 = 6500
Ramesh's SI = (15000 × 9 × 3)/100 = 4050. Suresh's SI = (18000 × 8 × 3)/100 = 4320. Difference = 270. [Note: Check calculation - 4320-4050=270, closest is B]
If amount = 2P, then SI = P. Using P = (P × R × 10)/100; 100 = 10R; R = 10% p.a.
SI = (24000 × 8.5 × 4)/100 = 8160
SI = 11700 - 9000 = 2700. Using T = (SI × 100)/(P × R) = (2700 × 100)/(9000 × 15) = 2 years
SI = 8640 - 7200 = 1440. Using SI = (P × R × T)/100; 1440 = (7200 × R × 2)/100; R = 10%