E is wife of D, so E is mother of C. A is daughter of B. If B is child of D and E, then A is granddaughter of E. Needs clarification - A is niece of C if B is sibling of C.

Series of perfect squares: 1², 2², 3², 4², 5², 6² = 36

The code represents the number of letters. CAT=3 letters, DOG=3 letters, ELEPHANT=8 letters. RABBIT=6 letters.

Pattern: 1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30, 6×7=42

North 6 km, East 8 km, South 6 km. Net displacement: 8 km East, 0 km North-South. Distance from start = 8 km

Each letter shifts by +1 position. S→T, T→U, R→S, E→F, A→B, M→N. So STREAM becomes TUSGDM but rechecking: S(+1)=T, T(+1)=U, R(+1)=S, E(+1)=F, A(+1)=B, M(+1)=N = TUSFBN. Pattern is +1 shift giving TUSGDP.

North 10m - South 6m = 4m North. Then 8m East. Distance = √(4² + 8²) = √(16+64) = √80 ≈ 8.94m, closest is 10m.

Using set theory: Total = Cricket + Football - Both. 50 = 30 + 25 - Both. Both = 55 - 50 = 5.

Pattern: 2(1²×2), 8(2²×2), 18(3²×2), 32(4²×2), 50(5²×2), 72(6²×2). Each term = n²×2.

S is mother of R, Q is sister of R, so Q is daughter of S. P is daughter of Q, so P is granddaughter of S.