Two articles are sold for ₹960 each. On the first article, there is a profit of 20%, and on the second, there is a loss of 20%. What is the net loss percentage on the entire transaction?
Answer: C
Step 1: For first article with 20% profit: SP = ₹960, so CP₁ = 1960.20 = ₹800.
Step 2: For second article with 20% loss: SP = ₹960, so CP₂ = 0960.80 = ₹1,200.
Step 3: Total CP = 2,000, Total SP = 1,920.
Loss% = (200080) × 100 = 4%.
So option C is correct.
Q.64Easy
A shopkeeper sells pens at ₹12 each, making a profit of 50%. How much does he spend to buy 180 pens?
Answer: A
Step 1: SP = ₹12, Profit = 50%, so CP = 112.50 = ₹8 per pen.
Step 2: Cost for 180 pens = 8 × 180 = ₹1,440.
So option A is correct.
Q.65Easy
At what rate of simple interest per annum will ₹2,400 become ₹2,928 in 2 years?
Answer: B
Step 1: Interest = 2,928 - 2,400 = ₹528.
Step 2: Using SI = (P × R × T) / 100, we get 528 = (2,400 × R × 2) / 100.
Step 3: 528 = 48R, so R = 11% p.a.
Option B is correct.
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Q.66Easy
In how many years will ₹3,600 amount to ₹4,392 at 11% simple interest per annum?
Answer: A
Step 1: Interest = 4,392 - 3,600 = ₹792.
Step 2: Using SI = (P × R × T) / 100, we get 792 = (3,600 × 11 × T) / 100.
Step 3: 792 = 396T, so T = 2 years.
Option A is correct.
Q.67Easy
Priya borrowed ₹8,000 from a moneylender at 15% simple interest per annum. If she paid ₹3,600 as interest, for how long did she borrow the money?
Answer: C
Using SI = (P × R × T) / 100, we have 3,600 = (8,000 × 15 × T) / 100.
Step 1: 3,600 = 1,200T.
Step 2: T = 3,1600,200 = 3 years.
Option C is correct.
Q.68Medium
A bank offers 7.5% simple interest per annum on fixed deposits. If Arun deposits ₹12,000, what will be the total amount after 4 years?
Step 2: Amount = Principal + SI = 12,000 + 3,600 = ₹15,600.
Option A is correct.
Q.69Medium
Two equal sums of money are invested at simple interest. The first at 9% p.a. for 5 years and the second at 6% p.a. for 8 years. If the difference in their interests is ₹840, what is the sum invested?
Mohan invested a certain sum at simple interest. If he had invested ₹5,000 more at the same rate, he would have earned ₹1,200 more interest in 4 years. What is the rate of interest per annum?
Answer: B
Step 1: Extra interest earned on ₹5,000 in 4 years = ₹1,200.
Step 2: Using SI = (P × R × T) / 100, we have 1,200 = (5,000 × R × 4) / 100.
Step 3: 1,200 = 200R.
Step 4: R = 1,200200 = 6% p.a.
Option B is correct.
Q.71Easy
Raj invested ₹12,000 at 8% per annum compound interest. What will be the amount after 2 years?
Answer: A
Step 1: Use compound interest formula A = P(1 + r/100)^n.
A sum of money doubles itself at 10% per annum compound interest. In how many years will it double?
Answer: A
Step 1: Use formula 2P = P(1.10)^n where 2P is the doubled amount.
Step 2: Divide by P to get 2 = (1.10)^n.
Step 3: Taking log: n = log(2)/log(1.10) = 0.0301.0414 ≈ 7.2 years.
Q.73Medium
At what rate per annum will ₹25,000 amount to ₹29,160 in 2 years at compound interest?
Answer: A
Step 1: Use formula A = P(1 + r/100)^n.
Step 2: 29160 = 25000(1 + r/100)^2.
Step 3: (1 + r/100)^2 = 2500029160 = 1.1664.
Step 4: 1 + r/100 = √1.1664 = 1.08.
Step 5: r/100 = 0.08, so r = 8% per annum.
Q.74Medium
A company invested ₹40,000 in a scheme offering 10% per annum compound interest. If the interest is compounded quarterly, what will be the maturity amount after 1 year?
Answer: C
Step 1: For quarterly compounding, use A = P(1 + r/400)^(4n).