Quantitative Aptitude - MCQ Practice Questions

Total distance = 200 + 100 = 300 m. Speed = 54 km/h = 15 m/s. Time = $\frac{300}{15}$ = 20 seconds

Total distance = 5×3 + 4×2 = 15 + 8 = 23 km. Total time = 5 hours. Avg speed = $\frac{23}{5}$ = 4.6 km/h

After 20% discount = 1000 × 0.80 = ₹800. After 10% discount = 800 × 0.90 = ₹720

SI₁ = (1000 × 10 × 3)/100 = 300. SI₂ = (2000 × 12 × 2)/100 = 480. Total = 300 + 480 = ₹780 (closest: should verify - 300+480=780, option A)

A's rate = $\frac{1}{30}$, B's rate = $\frac{1}{40}$. Combined rate = $\frac{7}{120}$. Work in 10 days = $\frac{70}{120}$. Remaining = $\frac{50}{120}$. B alone = ($\frac{50}{120}$)/($\frac{1}{40}$) = 16.67 days. (Re-check: Remaining work = 1 - 10($\frac{1}{30}$ + $\frac{1}{40}$) = 1 - 10×$\frac{7}{120}$ = $\frac{50}{120}$. Time for B = ($\frac{50}{120}$)÷($\frac{1}{40}$) = $\frac{50}{120}$ × 40 = 16.67 ≈ 16-17 days, check options)

SP = CP × 1.20. 480 = CP × 1.20. CP = $\frac{480}{1}$.20 = ₹400

Fill rate = $\frac{1}{10}$, Empty rate = $\frac{1}{15}$. Net = $\frac{1}{10}$ - $\frac{1}{15}$ = $\frac{1}{30}$. Time = 30 hours

Amount = P(1.10)³ = P × 1.331 = 1331. P = ₹1000

Let CP = 100. MP = 140. For 12% profit, SP = 112. Discount = 140 - 112 = 28. Discount % = $\frac{28}{140}$ × 100 = 20%

Let A, B, C complete work in a, b, c days respectively. 1/a + 1/b = $\frac{1}{12}$, 1/b + 1/c = $\frac{1}{15}$, 1/a + 1/c = $\frac{1}{20}$. Adding all three: 2(1/a + 1/b + 1/c) = $\frac{1}{12}$ + $\frac{1}{15}$ + $\frac{1}{20}$ = $\frac{12}{60}$ = $\frac{1}{5}$. So 1/a + 1/b + 1/c = $\frac{1}{10}$. Therefore, 1/a = $\frac{1}{10}$ - $\frac{1}{15}$ = $\frac{1}{30}$. A completes work in 30 days.

Let original price = 100. After 15% increase: 115. After 15% decrease: 115 × 0.85 = 97.75. Change = 97.75 - 100 = -2.25. Percentage change = -2.25%.

To find the total salary, we need to determine what percentage is saved, then use it to calculate the full amount.

Step 1: Find the percentage spent

The man spends money on food and rent:

Step 2: Find the percentage saved

Since total salary = 100%, the remaining amount is saved:

Step 3: Set up the equation

If 30% of his salary equals ₹3000:

Step 4: Solve for total salary

Verification: 40% of ₹10,000 = ₹4,000 (food); 30% of ₹10,000 = ₹3,000 (rent); Remaining = ₹10,000 − ₹7,000 = ₹3,000 ✓

**Answer: The total monthly salary is $₹10,000$ (Option A)**

Let original price = 100. After 20% increase: 120. After 10% increase: 120 × 1.10 = 132. Total increase = 32%.

Let MP = x. SP = x × (1 - 0.12) = 0.88x = 440. x = $\frac{440}{0}$.88 = 500.

Increase = 30,000 - 25,000 = 5,000. Percentage = (5,$\frac{000}{25}$,000) × 100 = 20%.

Let CP of 1 article = 1. CP of 8 = 8. SP of 10 = 8, so SP of 1 = 0.8. Loss = 1 - 0.8 = 0.2 = 20%.

Average = (65 + 75)/2 = $\frac{140}{2}$ = 70%.

Let number = 100. After 50% increase: 150. After 50% decrease: 150 × 0.5 = 75. Net change = (75-100)/100 × 100 = -25%.

New production = 5000 × (1 - 0.30) = 5000 × 0.70 = 3500 units.

Total parts = 3 + 2 = 5. Girls = $\frac{2}{5}$ = 0.4 = 40%.