Quantitative Aptitude - MCQ Practice Questions

Let CP = 100. MP = 160. SP = 160 × 0.75 = 120. Profit% = 20%

SP = CP × (1 - loss%) = 800 × (1 - 0.125) = 800 × 0.875 = ₹700

Percentage increase = [(114-95)/95] × 100 = ($\frac{19}{95}$) × 100 = 20%

Projected revenue = 50 × 1.35 = ₹67.5 crore

Average percentage = (72 + 68 + 80)/3 = $\frac{220}{3}$ = 73.33%

Population in 2023 = 5,00,000 × 0.92 = 4,60,000. Population in 2024 = 4,60,000 × 1.10 = 5,06,000

SP = CP + Profit = 1,200 + (40% of 1,200) = 1,200 + 480 = ₹1,680

Profit:CP = 3:5. So if CP = 5, Profit = 3. Profit% = ($\frac{3}{5}$) × 100 = 60%

If original price = x, then 0.82x = 410. x = $\frac{410}{0}$.82 = ₹500

After 10% discount: 800 × 0.90 = ₹720. After 5% discount: 720 × 0.95 = ₹684

A's investment = 60,000 + (50% of 60,000) = 60,000 + 30,000 = ₹90,000

(x/100) × 250 = 75. x = (75 × 100)/250 = 30

For 20% gain at ₹1,200: CP = 1,$\frac{200}{1}$.20 = ₹1,000. For 20% loss at ₹1,200: CP = 1,$\frac{200}{0}$.80 = ₹1,500. Total CP = ₹2,500, Total SP = ₹2,400. Loss = ₹100. Loss% = ($\frac{100}{2}$,500) × 100 = 4%

# Depreciation Problem — Compound Decay

When a value depreciates by a fixed percentage annually, we use the compound depreciation formula: $V_n=V_0(1-r{)}^n$, where $V_0$ is the initial value, $r$ is the depreciation rate, and $n$ is the number of years.

Step 1: Identify the given values

Initial value: $V_0=₹8,00,000$

Annual depreciation rate: $r=15\%=0.15$

Time period: $n=2$ years

Step 2: Set up the depreciation formula

After each year, the car retains $(1-0.15)=0.85$ of its previous value.

Step 3: Substitute values

Step 4: Calculate step-by-step

First, find $(0.85{)}^2$:

Then multiply by the initial value:

Answer: The car's value after 2 years will be ₹5,78,000 (Option A)

Let original number = x. After 20% increase: 1.20x. After 15% decrease: 1.20x × 0.85 = 510. 1.02x = 510. x = 500

If 20% votes were invalid = 8,000, then total votes = 8,000 ÷ 0.20 = 40,000

Let original price = 100. After 25% increase = 125. After 20% decrease on 125 = 125 × 0.80 = 100. Net = (105-100)/100 × 100 = 5% increase

CP = 600, MP = 600 × 1.40 = 840, SP = 840 × 0.85 = 714. Profit% = (714-600)/600 × 100 = 19%

Let C = 100, B = 110, A = 110 × 1.20 = 132. A is 32% more than C

To find how many additional days are needed, we use the relationship between work completed and time, where work rate remains constant.

Step 1: Find the daily work rate

If 30% of the job is completed in 6 days, the daily rate is:

Step 2: Calculate total days needed for 80% of the job

At a constant rate of 5% per day, the time to complete 80% is:

Step 3: Find additional days needed

The worker has already spent 6 days on the first 30%. Additional days required:

Answer: The worker needs 10 more days to complete 80% of the job (Option A)