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Biochemistry

Metabolic pathways, enzymes, proteins

278 Q 3 Topics Take Test
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Difficulty: All Easy Medium Hard 111–120 of 278
Topics in Biochemistry
All Proteins & Enzymes 100 Carbohydrates 100 Lipids 78
Q.111 Medium Carbohydrates
Which enzyme deficiency causes Pompe disease (GSD Type II)?
A Glycogen phosphorylase
B Acid α-glucosidase
C Branching enzyme
D Muscle phosphofructokinase
Correct Answer:  B. Acid α-glucosidase
EXPLANATION

Pompe disease results from deficiency of acid α-glucosidase (lysosomal α-1,4-glucosidase), leading to accumulation of glycogen in lysosomes, especially in muscles and heart.

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Q.112 Medium Carbohydrates
What is the primary fate of pyruvate under anaerobic conditions in muscle during intense exercise?
A Conversion to oxaloacetate
B Conversion to alanine
C Conversion to lactate
D Direct entry into citric acid cycle
Correct Answer:  C. Conversion to lactate
EXPLANATION

Under anaerobic conditions, pyruvate is reduced to lactate by lactate dehydrogenase (LDH) to regenerate NAD+ for continued glycolysis.

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Q.113 Medium Carbohydrates
Which of the following conditions causes increased glycogenolysis in muscle tissue during exercise?
A High insulin levels
B Increased epinephrine and decreased ATP/AMP ratio
C Increased glucose-6-phosphatase activity
D Decreased calcium influx
Correct Answer:  B. Increased epinephrine and decreased ATP/AMP ratio
EXPLANATION

During exercise, epinephrine increases and ATP/AMP ratio decreases, both of which activate phosphorylase kinase and promote glycogenolysis.

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Q.114 Medium Carbohydrates
In the citric acid cycle, which carbohydrate-derived molecule enters directly after acetyl-CoA formation?
A Pyruvate
B Acetyl-CoA
C Oxaloacetate
D Citrate
Correct Answer:  D. Citrate
EXPLANATION

Acetyl-CoA condenses with oxaloacetate to form citrate, which enters the citric acid cycle. Citrate synthase catalyzes this reaction.

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Q.115 Easy Carbohydrates
Which of the following is a reducing sugar?
A Sucrose
B Trehalose
C Maltose
D Lactose is incorrect
Correct Answer:  C. Maltose
EXPLANATION

Maltose is a reducing sugar because it has a free anomeric carbon. Sucrose and trehalose are non-reducing sugars as both anomeric carbons are involved in glycosidic bonds.

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Q.116 Easy Carbohydrates
What is the net yield of ATP from the anaerobic metabolism of one molecule of glucose?
A 2 ATP
B 4 ATP
C 30 ATP
D 38 ATP
Correct Answer:  A. 2 ATP
EXPLANATION

Anaerobic glycolysis produces 4 ATP molecules but consumes 2 ATP, resulting in a net gain of 2 ATP per glucose molecule.

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Q.117 Easy Carbohydrates
Which enzyme is the rate-limiting step of glycolysis and is inhibited by ATP and citrate?
A Hexokinase
B Phosphofructokinase-1
C Pyruvate kinase
D Enolase
Correct Answer:  B. Phosphofructokinase-1
EXPLANATION

Phosphofructokinase-1 (PFK-1) catalyzes the phosphorylation of fructose-6-phosphate to fructose-1,6-bisphosphate and is subject to allosteric inhibition by ATP and citrate.

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Q.118 Easy Carbohydrates
In glycolysis, the conversion of glucose-6-phosphate to fructose-6-phosphate is catalyzed by which enzyme?
A Hexokinase
B Phosphoglucose isomerase
C Phosphofructokinase
D Aldolase
Correct Answer:  B. Phosphoglucose isomerase
EXPLANATION

Phosphoglucose isomerase catalyzes the isomerization of glucose-6-phosphate to fructose-6-phosphate in the second step of glycolysis.

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Q.119 Easy Carbohydrates
Which of the following carbohydrates is classified as a pentose sugar?
A Ribose
B Glucose
C Galactose
D Fructose
Correct Answer:  A. Ribose
EXPLANATION

Ribose is a 5-carbon (pentose) sugar, while glucose, galactose, and fructose are hexoses (6-carbon sugars).

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Q.120 Medium Carbohydrates
Which statement best describes the relationship between glycogen structure and its metabolic advantages?
A Linear structure allows rapid glucose mobilization
B Branched structure with α-1,6-bonds increases solubility and accessibility to enzymes, enabling rapid glucose release
C Helical structure prevents enzymatic degradation
D Compact structure minimizes cellular volume occupied
Correct Answer:  B. Branched structure with α-1,6-bonds increases solubility and accessibility to enzymes, enabling rapid glucose release
EXPLANATION

Glycogen's highly branched structure with α-1,6-branch points every 8-12 glucose residues increases its solubility, provides multiple substrate sites for glycogen phosphorylase simultaneously, and enables rapid glucose mobilization during energy demands. This is metabolically superior to linear polymers.

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