An enzyme exhibits a Km of 2 mM and Vmax of 100 μmol/min. When substrate concentration is 6 mM and an allosteric inhibitor is added, the Vmax decreases to 50 μmol/min while Km remains unchanged. What type of inhibition is occurring?
ACompetitive inhibition
BNon-competitive inhibition
CUncompetitive inhibition
DMixed inhibition
Correct Answer:
B. Non-competitive inhibition
EXPLANATION
Non-competitive inhibition decreases Vmax while keeping Km constant. This occurs when an inhibitor binds to a site other than the active site (allosteric site), preventing product formation regardless of substrate concentration. The Km value remains unchanged because substrate binding affinity is unaffected.
A researcher studying protein folding observes that a newly synthesized polypeptide chain contains multiple disulfide bonds between cysteine residues. Which cellular compartment is most likely responsible for facilitating the formation of these disulfide bonds?
ARough endoplasmic reticulum and Golgi apparatus
BMitochondrial matrix
CCytoplasm
DLysosomal lumen
Correct Answer:
A. Rough endoplasmic reticulum and Golgi apparatus
EXPLANATION
Disulfide bonds are formed in oxidizing environments. The rough endoplasmic reticulum (RER) and Golgi apparatus maintain oxidizing conditions suitable for disulfide bond formation, unlike the reducing environment of the cytoplasm. The enzyme protein disulfide isomerase (PDI) facilitates this process in the ER lumen.
Which scenario best describes non-competitive enzyme inhibition kinetically?
AInhibitor binds to both free enzyme and enzyme-substrate complex with equal or different affinities, reducing Vmax while Km remains unchanged
BInhibitor only binds to free enzyme, increasing Km
CInhibitor irreversibly denatures the enzyme
DInhibitor reduces substrate availability in the reaction mixture
Correct Answer:
A. Inhibitor binds to both free enzyme and enzyme-substrate complex with equal or different affinities, reducing Vmax while Km remains unchanged
EXPLANATION
In non-competitive inhibition, the inhibitor binds to an allosteric site on both E and ES, preventing product formation. This decreases Vmax (fewer active enzymes) while Km remains unchanged (substrate binding affinity unaffected).
A protein exhibits a β-sheet structure rich in proline residues. Why is this structurally problematic?
AProline lacks a free NH group to form backbone hydrogen bonds in β-sheets
BProline causes excessive protein cross-linking
CProline increases hydrophobicity excessively
DProline participates in peptide bond cleavage
Correct Answer:
A. Proline lacks a free NH group to form backbone hydrogen bonds in β-sheets
EXPLANATION
Proline is an imino acid with its side chain bonded to the backbone nitrogen, eliminating the NH group needed for β-sheet hydrogen bonding between strands. High proline content disrupts β-sheet formation, commonly found in turns and loops instead.
A mutation changes a hydrophobic valine residue to a charged aspartate in the hydrophobic core of a globular protein. What is the most likely consequence?
AProtein instability and misfolding due to disruption of hydrophobic interactions
BEnhanced enzyme activity
CIncreased protein solubility with maintained function
DFormation of additional disulfide bonds
Correct Answer:
A. Protein instability and misfolding due to disruption of hydrophobic interactions
EXPLANATION
Substituting a nonpolar residue with a charged, hydrophilic one in the protein core disrupts critical hydrophobic interactions that stabilize the tertiary structure, leading to misfolding, aggregation, or degradation.
How does the proteasome recognize proteins marked for degradation in the ubiquitin-proteasome system?
ABy recognizing polyubiquitin chains (Lys48-linked) attached to lysine residues on target proteins
BBy scanning for hydrophobic amino acid sequences
CBy identifying proteins with exposed disulfide bonds
DBy sensing changes in protein charge
Correct Answer:
A. By recognizing polyubiquitin chains (Lys48-linked) attached to lysine residues on target proteins
EXPLANATION
E3 ubiquitin ligases catalyze the attachment of ubiquitin chains (primarily through Lys48 linkages) to lysine residues on target proteins. The 19S proteasomal subunit recognizes these polyubiquitin chains and unfolds the protein for degradation.
A student observes that an enzyme shows sigmoidal kinetics instead of Michaelis-Menten kinetics. What does this indicate?
AThe enzyme has multiple subunits and exhibits cooperative binding
BThe enzyme is completely inhibited
CThe enzyme lacks specificity
DThe substrate concentration is too high
Correct Answer:
A. The enzyme has multiple subunits and exhibits cooperative binding
EXPLANATION
Sigmoidal (S-shaped) kinetics indicate positive cooperativity, typical of allosteric enzymes with multiple subunits (e.g., aspartate transcarbamoylase). Binding of substrate to one subunit increases affinity in others.
Which proteolytic enzyme is responsible for activating trypsinogen to trypsin in the small intestine?
AEnteropeptidase
BChymotrypsin
CElastase
DCarboxypeptidase A
Correct Answer:
A. Enteropeptidase
EXPLANATION
Enteropeptidase (enterokinase), secreted by the duodenal mucosa, cleaves a specific peptide bond in trypsinogen to produce active trypsin, initiating the cascade of pancreatic protease activation.
In a temperature vs. enzyme activity graph, why does enzyme activity decrease above the optimal temperature?
AThe tertiary structure denatures and active site geometry is lost
BSubstrate concentration decreases
CCofactors are oxidized
DThe enzyme converts to its inactive zymogen form
Correct Answer:
A. The tertiary structure denatures and active site geometry is lost
EXPLANATION
Above optimal temperature, increased thermal energy disrupts hydrogen bonds and hydrophobic interactions maintaining the 3D structure, causing denaturation and loss of catalytic activity.
Which prosthetic group is found in cytochrome c oxidase?
AHeme a and copper centers
BOnly nicotinamide adenine dinucleotide
CFlavin adenine dinucleotide exclusively
DIron-sulfur clusters only
Correct Answer:
A. Heme a and copper centers
EXPLANATION
Cytochrome c oxidase (Complex IV) contains heme a, heme a3, and copper centers (CuA and CuB) essential for electron transfer and oxygen reduction to water.