Biochemistry — Carbohydrates
Metabolic pathways, enzymes, proteins
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Showing 1–10 of 100 questions in Carbohydrates
Q.1 Hard Carbohydrates
In the non-oxidative phase of the pentose phosphate pathway, ribulose-5-phosphate is converted to ribose-5-phosphate by the enzyme ribulose-5-phosphate isomerase. Which tissue shows MAXIMUM activity of this pathway and why?
A Red blood cells - for maintaining reducing power via NADPH
B Adipose tissue - for fatty acid synthesis requiring NADPH
C Bone marrow - for rapid nucleotide synthesis and cell division
D Liver - for glycogen storage and gluconeogenesis
Correct Answer:  C. Bone marrow - for rapid nucleotide synthesis and cell division
EXPLANATION

Bone marrow shows the highest pentose phosphate pathway activity because rapidly dividing cells require maximum ribose-5-phosphate for nucleotide (DNA/RNA) synthesis during cell division. While adipose tissue needs NADPH for lipogenesis and RBCs need it for antioxidant defense, bone marrow's continuous hematopoiesis demands the most nucleotide precursors. This is clinically relevant in leukemia and chemotherapy patients.

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Q.2 Medium Carbohydrates
A 45-year-old patient with Type 2 diabetes mellitus shows elevated fasting blood glucose (180 mg/dL) but normal HbA1c levels initially. Which carbohydrate metabolism pathway is primarily impaired in this patient's liver?
A Glycogenesis and increased gluconeogenesis
B Glycogenolysis and normal glycolysis
C Pentose phosphate pathway upregulation
D Lactate to pyruvate conversion
Correct Answer:  A. Glycogenesis and increased gluconeogenesis
EXPLANATION

Type 2 diabetes shows hepatic insulin resistance leading to impaired glycogenesis (reduced glycogen synthesis) and uncontrolled gluconeogenesis (excessive glucose production). This causes elevated fasting glucose despite normal HbA1c if glycemic control improves later. The liver fails to suppress glucose production in response to insulin.

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Q.3 Hard Carbohydrates
A patient with aldolase deficiency in fructose-1,6-bisphosphate (Class I aldolase) would show impaired glycolysis primarily because:
A Glucose-6-phosphate cannot be converted to fructose-6-phosphate
B Fructose-1,6-bisphosphate cannot be cleaved into triose phosphates
C Pyruvate cannot be formed from glyceraldehyde-3-phosphate
D Lactate cannot be converted to glucose
Correct Answer:  B. Fructose-1,6-bisphosphate cannot be cleaved into triose phosphates
EXPLANATION

Aldolase A catalyzes the cleavage of fructose-1,6-bisphosphate into DHAP and G3P. Its deficiency blocks glycolysis at this critical step.

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Q.4 Medium Carbohydrates
Which adaptation occurs in liver during prolonged fasting to maintain blood glucose?
A Increased glycogenolysis only
B Increased gluconeogenesis from lactate and amino acids
C Increased lipogenesis
D Increased glycogen synthesis
Correct Answer:  B. Increased gluconeogenesis from lactate and amino acids
EXPLANATION

After 8-12 hours of fasting, hepatic glycogen depletes. The liver then relies on gluconeogenesis from Cori cycle lactate and amino acids to maintain blood glucose.

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Q.5 Medium Carbohydrates
During fasting, which hormonal change directly increases hepatic glycogenolysis?
A Increased insulin and decreased glucagon
B Increased glucagon and epinephrine
C Increased cortisol and growth hormone only
D Increased somatostatin levels
Correct Answer:  B. Increased glucagon and epinephrine
EXPLANATION

Glucagon and epinephrine activate phosphorylation cascades that activate glycogen phosphorylase and inactivate glycogen synthase, promoting glycogenolysis.

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Q.6 Medium Carbohydrates
The Haworth projection of glucose differs from its Fischer projection. Which structural feature is best represented in Haworth projection?
A Linear conformation of glucose
B Cyclic hemiacetal structure with anomeric carbon
C Three-dimensional configuration of all carbons
D Stereoisomeric relationships between sugars
Correct Answer:  B. Cyclic hemiacetal structure with anomeric carbon
EXPLANATION

Haworth projection depicts the cyclic hemiacetal structure of glucose in its pyranose form, clearly showing the anomeric carbon and ring geometry.

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Q.7 Hard Carbohydrates
A diabetic patient shows impaired glucose utilization despite high blood glucose. Which enzyme's activity is most likely reduced?
A Glucokinase in beta cells
B Phosphofructokinase in muscle
C Glycogen phosphorylase in liver
D Hexokinase in tissues
Correct Answer:  A. Glucokinase in beta cells
EXPLANATION

In diabetes, impaired insulin secretion (due to reduced glucokinase in beta cells) leads to inadequate glucose sensing and utilization by tissues despite hyperglycemia.

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Q.8 Easy Carbohydrates
Which of the following carbohydrates does NOT undergo glycolysis?
A Glucose
B Mannose
C Cellulose
D Galactose
Correct Answer:  C. Cellulose
EXPLANATION

Cellulose is a β-1,4-linked glucose polymer that humans cannot digest due to lack of cellulase enzyme. It cannot enter glycolysis.

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Q.9 Medium Carbohydrates
In the pentose phosphate pathway, the oxidative phase generates NADPH. Which metabolic process primarily utilizes this NADPH in fed state?
A Glycolysis
B Ketone body synthesis
C Fatty acid and cholesterol synthesis
D Oxidative phosphorylation
Correct Answer:  C. Fatty acid and cholesterol synthesis
EXPLANATION

NADPH from the oxidative pentose phosphate pathway is essential for reductive biosynthesis of fatty acids and cholesterol, which occur predominantly in the fed state.

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Q.10 Hard Carbohydrates
A 6-year-old child presents with muscle pain and myoglobinuria after exercise. Muscle biopsy shows normal glycogen structure but elevated content. This is consistent with:
A Branching enzyme deficiency
B Muscle phosphorylase deficiency
C Lysosomal acid maltase deficiency
D Liver phosphorylase deficiency
Correct Answer:  B. Muscle phosphorylase deficiency
EXPLANATION

McArdle disease (GSD Type V) results from muscle phosphorylase deficiency. Glycogen accumulates but is structurally normal. Exercise intolerance and myoglobinuria are characteristic.

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