Home Subjects Biochemistry Proteins & Enzymes

Biochemistry
Proteins & Enzymes

Metabolic pathways, enzymes, proteins

100 Q 3 Topics Take Test
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Difficulty: All Easy Medium Hard 51–60 of 100
Topics in Biochemistry
All Proteins & Enzymes 100 Carbohydrates 100 Lipids 78
Q.51 Medium Proteins & Enzymes
Which post-translational modification is essential for the activation of blood clotting cascade and involves γ-carboxylation of glutamate residues?
A Phosphorylation
B Acetylation
C Hydroxylation and carboxylation (requires vitamin K as cofactor)
D Ubiquitination
Correct Answer:  C. Hydroxylation and carboxylation (requires vitamin K as cofactor)
EXPLANATION

Vitamin K-dependent carboxylation of glutamate residues in prothrombin and other clotting factors creates γ-carboxyglutamate residues that coordinate Ca2+ ions, essential for binding to phospholipid membranes and clotting cascade progression.

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In the context of enzyme kinetics, what does the turnover number (kcat) represent?
A The number of substrate molecules converted to product per unit time under saturating conditions
B The substrate concentration at half-maximum velocity
C The number of substrate molecules an enzyme can bind per second
D The rate constant for enzyme-substrate complex formation
Correct Answer:  A. The number of substrate molecules converted to product per unit time under saturating conditions
EXPLANATION

Turnover number (kcat = Vmax/[E]total) represents the number of substrate molecules converted to product per enzyme molecule per unit time at maximum velocity. It indicates catalytic efficiency when substrate is saturating.

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Which of the following proteases is secreted as an inactive zymogen and requires trypsin for its activation?
A Elastase
B Chymotrypsin
C Pepsin
D Caspase-3
Correct Answer:  B. Chymotrypsin
EXPLANATION

Chymotrypsin is secreted as chymotrypsinogen. Trypsin (activated by enterokinase) cleaves a specific dipeptide from chymotrypsinogen to generate active chymotrypsin, which then undergoes autolytic cleavage for full activation.

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During protein folding, which molecular chaperone is primarily responsible for preventing aggregation and facilitating ATP-dependent unfolding in prokaryotes?
A Hsp70
B Hsp90
C GroEL/GroES
D Peptidyl prolyl isomerase
Correct Answer:  C. GroEL/GroES
EXPLANATION

GroEL/GroES in prokaryotes forms a barrel-like structure that creates an isolated environment for protein folding. GroEL binds unfolded proteins using ATP hydrolysis, providing conformational assistance distinct from Hsp70's role in preventing aggregation.

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Q.55 Medium Proteins & Enzymes
What is the primary function of protein phosphatase 2A (PP2A) in cellular signaling?
A It phosphorylates serine and threonine residues on target proteins
B It dephosphorylates phosphorylated proteins, reversing kinase action and serving as a major tumor suppressor
C It exclusively dephosphorylates tyrosine residues
D It cleaves peptide bonds at acidic residues
Correct Answer:  B. It dephosphorylates phosphorylated proteins, reversing kinase action and serving as a major tumor suppressor
EXPLANATION

PP2A is a major serine/threonine phosphatase that plays crucial roles in reversing kinase-mediated phosphorylation. Its dysfunction is associated with various cancers, making it an important tumor suppressor enzyme.

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Q.56 Medium Proteins & Enzymes
A patient with phenylketonuria (PKU) lacks functional phenylalanine hydroxylase. Which cofactor is essential for this enzyme's activity?
A NAD+
B Tetrahydrobiopterin (BH4)
C FAD
D Heme iron (Fe2+)
Correct Answer:  B. Tetrahydrobiopterin (BH4)
EXPLANATION

Phenylalanine hydroxylase requires tetrahydrobiopterin (BH4) as a cofactor for the hydroxylation of phenylalanine to tyrosine. Mutations in this enzyme or BH4 synthesis lead to PKU, causing intellectual disability if untreated.

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Q.57 Medium Proteins & Enzymes
Which of the following statements about allosteric enzymes is correct?
A They follow Michaelis-Menten kinetics and have a linear Lineweaver-Burk plot
B They exhibit sigmoidal (S-shaped) velocity vs. substrate concentration curves due to cooperative binding
C Allosteric inhibitors always bind to the active site of the enzyme
D They have only one subunit and cannot be regulated
Correct Answer:  B. They exhibit sigmoidal (S-shaped) velocity vs. substrate concentration curves due to cooperative binding
EXPLANATION

Allosteric enzymes like phosphofructokinase show cooperative binding where substrate binding at one subunit increases affinity at others. This produces an S-shaped curve rather than the hyperbolic Michaelis-Menten curve, allowing for better metabolic control.

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In protein synthesis, which aminoacyl-tRNA synthetase error rate is approximately 1 in 10,000, ensuring high fidelity?
A Through initial selection based on ATP hydrolysis
B Through a proofreading mechanism that hydrolyzes incorrectly charged tRNA
C Through ribosomal surveillance mechanisms only
D Through multiple rounds of GTP hydrolysis in the ribosome
Correct Answer:  B. Through a proofreading mechanism that hydrolyzes incorrectly charged tRNA
EXPLANATION

Aminoacyl-tRNA synthetases achieve high fidelity through a two-step selection process: initial selection during aminoacylation and a second proofreading step (editing) that hydrolyzes incorrectly charged tRNA-amino acid complexes before they leave the enzyme.

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Collagen, the most abundant protein in mammals, contains which unusual amino acid at every third position?
A Proline
B Glycine
C Hydroxyproline
D Lysine
Correct Answer:  B. Glycine
EXPLANATION

Collagen has a characteristic Gly-X-Y tripeptide repeat pattern where glycine appears at every third position. This allows tight packing in the triple helix structure. Hydroxyproline (formed by post-translational modification of proline) stabilizes the helix.

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Q.60 Medium Proteins & Enzymes
What is the primary difference between competitive and non-competitive enzyme inhibition in terms of Vmax and Km?
A Competitive inhibition decreases Vmax; non-competitive inhibition decreases Km
B Competitive inhibition increases Km without affecting Vmax; non-competitive inhibition decreases Vmax
C Competitive inhibition affects both Km and Vmax equally
D Both types of inhibition only affect the enzyme's cofactor binding
Correct Answer:  B. Competitive inhibition increases Km without affecting Vmax; non-competitive inhibition decreases Vmax
EXPLANATION

Competitive inhibitors compete with substrate for the active site, increasing apparent Km while Vmax remains unchanged. Non-competitive inhibitors bind to a site other than the active site, decreasing Vmax without changing Km.

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