1/10+1/15=5/30=1/6. Together=6 days.
R=100/8=12.5%.
Sum=140. New sum=100. Excluded=40.
CI=10000×1.1²-10000=12100-10000=Rs 2100.
Net=1/6-1/12=1/12. Time=12 hrs.
CP=840×100/120=Rs 700.
5!=120.
Since 9 and 11 are coprime (HCF = 1), the number must be divisible by 9 × 11 = 99.
Let numbers be x, x+2, x+4, x+6, x+8. Sum = 5x + 20 = 120, so x = 20. Largest = 20 + 8 = 28.
# Step-by-Step Explanation
Step 1: Find the Least Common Multiple (LCM)
To find numbers divisible by both 6 and 9, we need numbers divisible by their LCM.
- 6 = 2 × 3
- 9 = 3²
- LCM(6,9) = 2 × 3² = 18
Step 2: Identify the requirement
We need numbers between 1 and 100 that are divisible by 18.
Step 3: List all multiples of 18 in this range
- 18 × 1 = 18 ✓
- 18 × 2 = 36 ✓
- 18 × 3 = 54 ✓
- 18 × 4 = 72 ✓
- 18 × 5 = 90 ✓
- 18 × 6 = 108 ✗ (exceeds 100)
Step 4: Count the valid numbers
The multiples are: 18, 36, 54, 72, and 90 = 5 numbers
Conclusion:
Answer A: 5 is correct because numbers divisible by both 6 and 9 must be divisible by their LCM of 18. Only five multiples of 18 fall between 1 and 100. The other options overcounted by either miscalculating the LCM or incorrectly counting multiples.
