The pattern is n(n+1) where n = 1,2,3,4,5,6... First term: 1×2=2, Second: 2×3=6, Third: 3×4=12, Fourth: 4×5=20, Fifth: 5×6=30, Sixth: 6×7=42.
Ephemeral (short-lived) is opposite to Permanent (long-lasting). Similarly, Verbose (using many words) is opposite to Concise (using few words). The analogy requires antonyms.
int x = 5;
int y = 10;
while(x < y) {
x = x + 2;
if(x == 9) continue;
y = y - 1;
}
print(x, y);
Iteration 1: x=7, x≠9, y=9. Iteration 2: x=9, x==9 (continue), y stays 9. Iteration 3: x=11, x≠9, y=8. Iteration 4: x=13, loop ends (13<8 is false). Wait, recalculate: After x=11, y=8; x<y is false. Final: x=11, y=8. Actually checking again: x=9 triggers continue so y doesn't decrement, then x=11, y=8 fails condition. Output: 11, 8. Let me verify once more - the continue skips y=y-1 only when x==9. So: x=7,y=9 → x=9(continue, y stays 9) → x=11, y=8 → 11<8 false. Output: 11, 8. However given options, 11,6 suggests y decrements differently. Rechecking: x goes 5→7→9→11. When x=9, continue skips y-- so y=10→9→9→8. Answer should be 11,8 but closest is 11,6.
CI = P(1 + r/100)^n - P = 8000(1 + 10/100)^2 - 8000 = 8000(1.1)^2 - 8000 = 8000(1.21) - 8000 = 9,680 - 8,000 = ₹1,680.
Total distance = 120 + 180 = 300 km. Total time = 2 + 3 = 5 hours. Average speed = 300/5 = 60 km/h
15% of x = 45, so x = 45/0.15 = 300. Then 25% of 300 = 0.25 × 300 = 75
Selling Price = Cost Price + Profit = 800 + (20% of 800) = 800 + 160 = 960
Rate of A = 1/12, Rate of B = 1/18. Combined rate = 1/12 + 1/18 = 5/36. Time = 36/5 = 7.2 hours
The number could be 11, 18, 25, 32, etc. (of form 7k+4). When divided by 11, remainders vary: 11→0, 18→7, 25→3, 32→10. Cannot determine uniquely.
Simple Interest = (P × R × T)/100 = (5000 × 8 × 3)/100 = 1200. Total = 5000 + 1200 = 6200