A mobile phone is sold for ₹18,900 at a profit of 35%. What is its cost price?

The correct answer is B: ₹14,000. Step 1: Selling Price = ₹18,900 and Profit = 35%. Step 2: CP = SP / (1 + Profit%/100) = 18,900 / 1.35 = ₹14,000. Step 3: Verification: Profit = 14,000 × 0.35 = ₹4,900; SP = 14,000 + 4,900 = ₹18,900 ✓. So option B is correct.

A number is increased by 20% and then decreased by 15%. If the final number is 510, what was the original number?

The correct answer is A: 500. Let original number = x. After 20% increase: 1.20x. After 15% decrease: 1.20x × 0.85 = 510. 1.02x = 510. x = 500

Two equal sums of money are invested at simple interest. The first at 9% p.a. for 5 years and the second at 6% p.a. for 8 years. If the difference in their interests is ₹840, what is the sum invested?

The correct answer is A: ₹2,000. Let sum = P. Step 1: SI₁ = (P × 9 × 5) / 100 = 45P/100. Step 2: SI₂ = (P × 6 × 8) / 100 = 48P/100. Step 3: Difference = 48P/100 - 45P/100 = 3P/100 = 840. Step 4: P = 84,000 / 3 = ₹2,000. Option A is correct.

The compound interest on ₹8,000 at 15% per annum for 2 years is how much less than the simple interest on the same sum at the same rate and period?

The correct answer is A: ₹180. Step 1: Simple Interest = (8000 × 15 × 2)/100 = ₹2,400. Step 2: Compound Interest = 8000(1.15)^2 - 8000 = 8000(1.3225 - 1) = 8000 × 0.3225 = ₹2,580. Wait, that's more. Recalculating: CI = 8000(1.15)^2 - 8000 = 10,580 - 8000 = ₹2,580. SI = ₹2,400. Difference = 2580 - 2400 = ₹180. CI is more, not less

Three friends invested ₹10,000 each at 8%, 10%, and 12% simple interest respectively for 3 years. What is the total interest earned by all three?

The correct answer is A: ₹9,000. Simple interest is calculated as a percentage of the principal amount and remains constant each year. **Step 1: Calculate Interest for Friend 1 (8% rate)** Friend 1 invested ₹10,000 at 8% simple interest for 3 years. $$\text{Interest} = \frac{P \times R \times T}{100} = \frac{10,000 \times 8 \times

Corporate & IT Interview Preparation

Quantitative Aptitude

Aptitude · Reasoning · English · CS — Corporate & Campus Interview Prep

428 Questions 7 Topics Take Test

Showing 301–310 of 428 questions

Q.301 Easy HCF and LCM

A train travels 360 km in 6 hours. Find the time taken to travel 600 km at the same speed.

A 8 hours

B 10 hours

C 12 hours

D 15 hours

Correct Answer: B. 10 hours

Explanation:

Speed = 360/6 = 60 km/h. Time = Distance/Speed = 600/60 = 10 hours

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Q.302 Easy HCF and LCM

The LCM of 24 and 36 is?

A 48

B 72

C 96

D 144

Correct Answer: B. 72

Explanation:

24 = 2³×3, 36 = 2²×3². LCM = 2³×3² = 8×9 = 72

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Q.303 Easy HCF and LCM

Simple Interest on ₹8000 at 6% per annum for 2.5 years is?

A ₹1000

B ₹1100

C ₹1200

D ₹1500

Correct Answer: C. ₹1200

Explanation:

SI = (P×R×T)/100 = (8000×6×2.5)/100 = 120000/100 = ₹1200

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Q.304 Easy HCF and LCM

LCM of three numbers 12, 18, and 24 is?

A 36

B 48

C 72

D 144

Correct Answer: C. 72

Explanation:

12 = 2²×3, 18 = 2×3², 24 = 2³×3. LCM = 2³×3² = 8×9 = 72

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Q.305 Easy HCF and LCM

A person buys an article for ₹400 and sells it for ₹520. What is the profit percentage?

A 25%

B 30%

C 35%

D 40%

Correct Answer: B. 30%

Explanation:

Profit = 520 - 400 = ₹120. Profit% = (120/400)×100 = 30%

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Q.306 Easy HCF and LCM

A boat's effective speed in still water is 10 km/h and current speed is 2 km/h. Time to travel 36 km downstream is?

A 2.5 hours

B 3 hours

C 3.5 hours

D 4 hours

Correct Answer: B. 3 hours

Explanation:

Downstream speed = 10 + 2 = 12 km/h. Time = Distance/Speed = 36/12 = 3 hours

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Q.307 Easy HCF and LCM

If the HCF of 75 and 125 is 'h' and LCM is 'l', then h×l equals?

A 9375

B 8500

C 7500

D 6250

Correct Answer: A. 9375

Explanation:

HCF × LCM = Product of numbers = 75 × 125 = 9375

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Q.308 Easy HCF and LCM

The HCF of two numbers is 12 and their LCM is 360. If one number is 60, find the other number.

A 72

B 84

C 96

D 108

Correct Answer: A. 72

Explanation:

Using the formula: HCF × LCM = Product of two numbers. 12 × 360 = 60 × Other number. Other number = 4320/60 = 72

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Q.309 Easy HCF and LCM

A shopkeeper has 48 apples, 72 oranges, and 96 bananas. He wants to pack them into boxes such that each box contains the same number of items of each type. What is the maximum number of boxes needed?

A 12

B 18

C 24

D 36

Correct Answer: C. 24

Explanation:

Maximum boxes = HCF(48, 72, 96) = 24. Each box will have 2 apples, 3 oranges, and 4 bananas

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Q.310 Easy HCF and LCM

A man buys an article for ₹800 and sells it at a 25% profit. What is the selling price?

A ₹900

B ₹1000

C ₹1200

D ₹1400

Correct Answer: B. ₹1000

Explanation:

Selling Price = Cost Price + Profit = 800 + (25% of 800) = 800 + 200 = ₹1000

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