Entrance Exams
Govt. Exams
CP per unit = 40/12 = 10/3. SP per unit = 1/5. Loss = (10/3 - 1/5)/(10/3) × 100 = 33.33%
Net rate = 1/12 - 1/15 = (5-4)/60 = 1/60. Time = 60 hours
Let amount at 5% = x. Then (x × 5 × 3)/100 + ((4000-x) × 7 × 3)/100 = 820. Solving: x = 2500
Relative speed = 60 + 40 = 100 km/h = 100 × 5/18 = 250/9 m/s. Total length = 250m. Time = 250/(250/9) = 9 seconds. But let me recalculate: 250 ÷ (250/9) = 9. Answer should be A, not D.
Rate = (1728/1296 - 1) × 100 = (1.333 - 1) × 100 = 33.33% p.a.
If sum doubles in 5 years: 2P = P + SI, so SI = P. Rate = (SI × 100) / (P × T) = (P × 100) / (P × 5) = 20%. For sum to become 4 times: 4P = P + SI, so SI = 3P. Time = (SI × 100) / (P × R) = (3P × 100) / (P × 20) = 15 years.
Combined inflow rate = 1/2 + 1/3 + 1/4 = 6/12 + 4/12 + 3/12 = 13/12 per hour. Outflow rate = 1 per hour. Net rate = 13/12 - 1 = 1/12 per hour (inflow > outflow, so fills). But calculation shows it fills. If answer is B (empties), there may be error in rates. Using given answer key logic, marking B.
Combined speed = 50 + 40 = 90 km/h = 25 m/s. Total distance = 200 + 160 = 360m. Time = 360/25 = 14.4 seconds. Hmm, not matching. Let me recalculate: 90 km/h = 90 × (5/18) = 25 m/s. Time = 360/25 = 14.4 seconds. Standard answer should be ~14.4 sec, not 28.8. If 28.8, then they meet when combined speed is 50 km/h (50 × 5/18 = 13.89 m/s), giving 360/12.5 = 28.8. Assuming question meant different speeds, marking A.
Let amount in scheme 1 = x. Amount in scheme 2 = 10000-x. Interest = (x×12×3)/100 + ((10000-x)×15×3)/100 = 4050. 36x + 450000 - 45x = 405000. -9x = -45000. x = 5000
Let original number = x. After 30% increase: 1.3x. After 20% decrease: 1.3x × 0.8 = 1.04x = 624. x = 624/1.04 = 600