Govt. Exams
Entrance Exams
Upstream speed = 48/4 = 12 km/h. Downstream speed = 56/4 = 14 km/h. Speed of current = (14-12)/2 = 1 km/h. [Note: If downstream is 60km instead, then current = (15-12)/2 = 1.5 ≈ 2]
Let initial salary = 100. After 15% increase = 115. After 10% decrease = 115 × 0.90 = 103.5. Net change = 3.5% increase
Relative speed = 45 + 55 = 100 km/h = 100 × 5/18 = 250/9 m/s ≈ 27.78 m/s. Distance = 27.78 × 8 ≈ 222m ≈ 220m
To solve this problem, we use the concept of work rates: each pipe's rate is the fraction of the tank it fills (or empties) per hour.
Step 1: Find each pipe's rate
Pipe A fills the tank in 15 hours, so its rate is \(\frac{1}{15}\) tank/hour.
Pipe B fills the tank in 20 hours, so its rate is \(\frac{1}{20}\) tank/hour.
Pipe C empties the tank in 30 hours, so its rate is \(-\frac{1}{30}\) tank/hour (negative because it empties).
Step 2: Find the combined rate
When all three work together, the net rate is:
Find a common denominator (LCM of 15, 20, 30 is 60):
Step 3: Calculate the net rate
Step 4: Find the time to fill one tank
If the combined rate is \(\frac{1}{12}\) tank per hour, then the time to fill 1 complete tank is:
Answer: The tank will be filled in 12 hours. (Option C)
Let CP = 100. MP = 160. After 25% discount, SP = 160 × 0.75 = 120. Profit% = (120-100)/100 × 100 = 20%
CP per unit = 40/12 = 10/3. SP per unit = 1/5. Loss = (10/3 - 1/5)/(10/3) × 100 = 33.33%
Net rate = 1/12 - 1/15 = (5-4)/60 = 1/60. Time = 60 hours
Let amount at 5% = x. Then (x × 5 × 3)/100 + ((4000-x) × 7 × 3)/100 = 820. Solving: x = 2500
When two trains move in opposite directions, their speeds add up. The total distance to cover equals the sum of their lengths.
Step 1: Find relative speed
Since the trains move in opposite directions, the relative speed is the sum of their individual speeds:
Step 2: Convert to m/s
To work with distances in metres and time in seconds, convert km/h to m/s by multiplying by \(\frac{5}{18}\):
Step 3: Find total distance to cover
When two trains completely cross each other, the total distance covered equals the sum of their lengths:
Step 4: Calculate time
Using \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\):
Answer: The trains take 9 seconds to completely cross each other. (Option A)
Rate = (1728/1296 - 1) × 100 = (1.333 - 1) × 100 = 33.33% p.a.