Govt Exam — Quantitative Aptitude
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Showing 21–30 of 429 questions
Q.21 Easy Profit and Loss
A mobile phone is sold for ₹18,900 at a profit of 35%. What is its cost price?
A ₹12,800
B ₹14,000
C ₹15,200
D ₹16,500
Correct Answer:  B. ₹14,000
Explanation:
Step 1: Selling Price = ₹18,900 and Profit = 35%.
Step 2: CP = SP / (1 + Profit%/100) = 18,900 / 1.35 = ₹14,000.
Step 3: Verification: Profit = 14,000 × 0.35 = ₹4,900; SP = 14,000 + 4,900 = ₹18,900 ✓.

So option B is correct.

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Q.22 Easy Profit and Loss
If a merchant sells rice at ₹56 per kg and makes a profit of 40%, at what price did he buy the rice?
A ₹35 per kg
B ₹38 per kg
C ₹40 per kg
D ₹42 per kg
Correct Answer:  C. ₹40 per kg
Explanation:
Step 1: Selling Price = ₹56 per kg and Profit = 40%.
Step 2: CP = SP / (1 + Profit%/100) = 56 / 1.40 = ₹40 per kg.
Step 3: Verification: Profit = 40 × 0.40 = ₹16; SP = 40 + 16 = ₹56 ✓.

So option C is correct.

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Q.23 Easy Profit and Loss
A bookstore purchases novels at ₹240 per unit and sells them at ₹288 per unit. What is the profit percentage?
A 18%
B 20%
C 22%
D 25%
Correct Answer:  B. 20%
Explanation:
Step 1: Cost Price (CP) = ₹240, Selling Price (SP) = ₹288.
Step 2: Profit = SP - CP = 288 - 240 = ₹48.
Step 3: Profit% = (Profit/CP) × 100 = (48/240) × 100 = 20%.

So option B is correct.

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Q.24 Easy Profit and Loss
If a watch is sold for ₹1,650 at a loss of 12%, what is its cost price?
A ₹1,875
B ₹1,850
C ₹1,920
D ₹1,800
Correct Answer:  A. ₹1,875
Explanation:
Step 1: Loss = 12%, so SP = 88% of CP.
Step 2: Let CP = x, then 0.88x = 1650.
Step 3: x = 1650/0.88 = ₹1,875.

So option A is correct.

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Q.25 Easy Profit and Loss
A shopkeeper sells pens at ₹12 each, making a profit of 50%. How much does he spend to buy 180 pens?
A ₹1,440
B ₹1,320
C ₹1,480
D ₹1,550
Correct Answer:  A. ₹1,440
Explanation:
Step 1: SP = ₹12, Profit = 50%, so CP = 12/1.50 = ₹8 per pen.
Step 2: Cost for 180 pens = 8 × 180 = ₹1,440.

So option A is correct.

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Q.26 Easy Simple Interest
At what rate of simple interest per annum will ₹2,400 become ₹2,928 in 2 years?
A 10% p.a.
B 11% p.a.
C 12% p.a.
D 13% p.a.
Correct Answer:  B. 11% p.a.
Explanation:
Step 1: Interest = 2,928 - 2,400 = ₹528.
Step 2: Using SI = (P × R × T) / 100, we get 528 = (2,400 × R × 2) / 100.
Step 3: 528 = 48R, so R = 11% p.a.

Option B is correct.

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Q.27 Easy Simple Interest
In how many years will ₹3,600 amount to ₹4,392 at 11% simple interest per annum?
A 2 years
B 2.5 years
C 3 years
D 3.5 years
Correct Answer:  A. 2 years
Explanation:
Step 1: Interest = 4,392 - 3,600 = ₹792.
Step 2: Using SI = (P × R × T) / 100, we get 792 = (3,600 × 11 × T) / 100.
Step 3: 792 = 396T, so T = 2 years.

Option A is correct.

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Q.28 Easy Simple Interest
Priya borrowed ₹8,000 from a moneylender at 15% simple interest per annum. If she paid ₹3,600 as interest, for how long did she borrow the money?
A 2 years
B 2.5 years
C 3 years
D 3.5 years
Correct Answer:  C. 3 years
Explanation:

Using SI = (P × R × T) / 100, we have 3,600 = (8,000 × 15 × T) / 100.

Step 1: 3,600 = 1,200T.
Step 2: T = 3,600 / 1,200 = 3 years.

Option C is correct.

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Q.29 Easy
Raj invested ₹12,000 at 8% per annum compound interest. What will be the amount after 2 years?
A ₹13,996.80
B ₹13,872.00
C ₹14,112.00
D ₹13,920.00
Correct Answer:  A. ₹13,996.80
Explanation:
Step 1: Use compound interest formula A = P(1 + r/100)^n.
Step 2: A = 12000(1 + 8/100)^2 = 12000(1.08)^2 = 12000 × 1.1664 = 13,996.80.
Step 3: The amount after 2 years is ₹13,996.80.
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Q.30 Easy
A sum of money doubles itself at 10% per annum compound interest. In how many years will it double?
A 7.2 years
B 7.5 years
C 8 years
D 6.5 years
Correct Answer:  A. 7.2 years
Explanation:
Step 1: Use formula 2P = P(1.10)^n where 2P is the doubled amount.
Step 2: Divide by P to get 2 = (1.10)^n.
Step 3: Taking log: n = log(2)/log(1.10) = 0.301/0.0414 ≈ 7.2 years.
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