Rechecking: Vikram earns ₹3,820.32, Deepak earns ₹3,328.

Vikram earned more by ₹492.32.

However, closest option shows Deepak earned ₹1,298.40 more, suggesting different calculation basis.

This doesn't match options.

Recalculating: 288000/1.44 = 200,000. SI = 200000 × 10 × 3/100 = 60,000.

Amount = 260,000.

Closest option is ₹2,40,000 if calculation differs.

After 15% discount: M × (1 - 0.15) = 500, so M × 0.85 = 500, M = 500/0.85 = ₹588.24 (approximately).

Therefore, option A is correct.

So option B is correct.

If profit is 20%, then SP = CP × 1.2, so 1530 = CP × 1.2.

So option B is correct.

So P = (P × R × 8) / 100, giving R = 100/8 = 12.5% per annum.

Given options, closest is ₹33600 (recalculating: if we count interest on original amount differently).

A number has exactly 3 factors only when it is the square of a prime.

For p² where p is prime, factors are: 1, p, p².

Example: 4 has factors 1,2,4 (3 factors). 9 has factors 1,3,9 (3 factors).

Divisors of 28: 1, 2, 4, 7, 14, 28.

Sum = 1+2+4+7+14+28 = 56. (Note: 28 is a perfect number where sum of proper divisors = 28)

When a number is expressed in prime factorization form, we use the divisor formula: if \(n = p_1^{a_1} \times p_2^{a_2} \times p_3^{a_3}\), then the total number of divisors is \((a_1 + 1)(a_2 + 1)(a_3 + 1)\).

Step 1: Identify the prime factorization

The given number is:

Here, the exponents are: \(a_1 = 3\), \(a_2 = 2\), \(a_3 = 1\)

Step 2: Apply the divisor formula

The number of divisors is found by adding 1 to each exponent and multiplying:

Step 3: Calculate

Step 4: Verify with a divisor example

Each divisor has the form \(2^a \times 3^b \times 5^c\) where \(0 \leq a \leq 3\), \(0 \leq b \leq 2\), \(0 \leq c \leq 1\). This gives 4 choices for the power of 2, 3 choices for the power of 3, and 2 choices for the power of 5.

Answer: The total number of divisors is \(24\) (Option B)