Charbagh Railway Station in Agra is closest to the Taj Mahal, one of India's most famous monuments and a UNESCO World Heritage Site.

Percentage increase = ((80 - 60) ÷ 60) × 100 = (20 ÷ 60) × 100 = 33.33%

Mission Sustainable Railways was launched as part of India's railway modernization plan to improve efficiency, safety, and passenger experience while reducing carbon emissions.

A gets a 1.5 hour head start (70 × 1.5 = 105 km). Relative speed = 90 - 70 = 20 km/h. Time to overtake = 105/20 = 5.25 hours after B departs.

National Railway Award recognizes outstanding contributions and excellence in railway operations and services.

When two objects move towards each other from different starting points and times, we find their meeting point by calculating the distance each covers until they meet.

Step 1: Calculate distance covered by Train A before Train B starts

Train A leaves at 6:00 AM and Train B leaves at 8:00 AM — a 2-hour head start.

\[

\text{Distance by Train A in 2 hours} = 75 \times 2 = 150\,\text{km}

\]

Remaining distance between trains at 8:00 AM:

\[

500 - 150 = 350\,\text{km}

\]

Step 2: Find relative speed of approach

Both trains now move towards each other. Their combined closing speed is:

\[

\text{Relative speed} = 75 + 85 = 160\,\text{km/h}

\]

Step 3: Calculate time to meet after 8:00 AM

Time for both trains to cover the remaining 350 km:

\[

\text{Time} = \frac{350}{160} = \frac{35}{16}\,\text{hours}

\]

Converting to hours and minutes:

\[

\frac{35}{16} = 2\frac{3}{16}\,\text{hours} = 2\,\text{hours} + \frac{3}{16} \times 60\,\text{minutes}

\]

\[

\frac{3}{16} \times 60 = 11.25\,\text{minutes} = 11\,\text{minutes and 15 seconds}

\]

Step 4: Add elapsed time to 8:00 AM

Meeting time:

\[

8:00\,\text{AM} + 2\,\text{hours}\,11\,\text{minutes}\,15\,\text{seconds} = 10:11:15\,\text{AM}

\]

Answer: The trains meet at \(10:11:15\,\text{AM}\) (Option A)

Railways cover approximately 35% of India's total transport network.

Let original speed = v km/h, original time = t hours. Distance = vt. New speed = 1.2v, new time = t-5. vt = 1.2v(t-5). Solving: t = 30 hours, v = 50 km/h.

Lucknow Railway Station in India has 6 platforms and is among the largest, though Grand Central has more functionally.

Average speed = 2ab/(a+b) = 2×60×80/(60+80) = 9600/140 = 68.57 km/h