By Vieta's formulas, sum of roots = -b/a
Using Pythagoras theorem: distance = √(3² + 4²) = √(9 + 16) = √25 = 5 km
Adding both equations: 5x + 5y = 25, so x + y = 5
Area = πr² = (22/7)×49 = 154 cm²
tan θ = 5/12, in right triangle opposite=5, adjacent=12, hypotenuse=13. sin θ = 5/13
∫(2x + 3)dx = x² + 3x + C
5² + 12² = 25 + 144 = 169 = 13². Satisfies Pythagoras theorem, so it's right-angled
x³ - 8 = (x-2)(x² + 2x + 4), so (x³ - 8)/(x - 2) = x² + 2x + 4
Let numbers be 3x and 5x. 3x + 5x = 64 → 8x = 64 → x = 8. Larger number = 5 × 8 = 40.
Quadratic equation is x² - (sum of roots)x + (product of roots) = 0, which gives x² - 7x + 10 = 0.
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