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Quantitative Aptitude

Quantitative aptitude questions for competitive exams

428 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 391–400 of 428
Topics in Quantitative Aptitude
Q.391 Easy Profit and Loss
If a vendor sells bananas at a loss of 15% and the cost price is ₹500 per kg, at what price does he sell per kg?
A ₹415
B ₹425
C ₹420
D ₹435
Correct Answer:  B. ₹425
EXPLANATION
Step 1: Loss = 15% of CP = 15% of 500 = ₹75.
Step 2: Selling Price = CP - Loss = 500 - 75 = ₹425 per kg.

So option B is correct.

Test
Q.392 Easy Profit and Loss
A merchant buys a shirt for ₹240 and sells it for ₹312. What is the profit percentage?
A 25%
B 30%
C 32%
D 28%
Correct Answer:  B. 30%
EXPLANATION
Step 1: Profit = Selling Price - Cost Price = 312 - 240 = ₹72.
Step 2: Profit% = (Profit/CP) × 100 = (72/240) × 100 = 30%.

So option B is correct.

Test
Q.393 Easy Percentage Percentage Decrease
A factory reduces its production by 18% due to lockdown. If the original production was 5,000 units per day, how many units are produced now?
A 4,000 units
B 4,050 units
C 4,100 units
D 4,150 units
Correct Answer:  C. 4,100 units
EXPLANATION
Step 1: Reduction in production = 18% of 5,000 = 0.18 × 5,000 = 900 units.
Step 2: Current production = 5,000 - 900 = 4,100 units per day.

Therefore, option C is correct.

Test
Q.394 Easy Percentage Percentage Application
The population of a town was 50,000 last year. If it increased by 8% this year, what is the current population?
A 53,500
B 54,000
C 54,500
D 55,000
Correct Answer:  B. 54,000
EXPLANATION
Step 1: Population increase = 8% of 50,000 = 0.08 × 50,000 = 4,000.
Step 2: Current population = 50,000 + 4,000 = 54,000.

Therefore, option B is correct.

Test
Q.395 Easy Percentage Profit and Cost Price
A shopkeeper buys an item for ₹250 and wants to earn a profit of 20%. At what price should the item be sold?
A ₹295
B ₹300
C ₹310
D ₹315
Correct Answer:  B. ₹300
EXPLANATION
Step 1: Profit = 20% of ₹250 = 0.20 × 250 = ₹50.
Step 2: Selling Price = Cost Price + Profit = 250 + 50 = ₹300.

Therefore, option B is correct.

Test
Q.396 Easy Percentage Percentage Calculation
A student scored 72 marks out of 120 in an exam. What is the percentage of marks obtained?
A 58%
B 60%
C 62%
D 65%
Correct Answer:  B. 60%
EXPLANATION
Step 1: Percentage = (Marks obtained/Total marks) × 100 = (72/120) × 100.
Step 2: = 0.6 × 100 = 60%.

Therefore, option B is correct.

Test
Q.397 Easy Percentage Percentage Increase
If the price of milk increases from ₹40 per liter to ₹50 per liter, what is the percentage increase?
A 20%
B 22.5%
C 25%
D 27.5%
Correct Answer:  C. 25%
EXPLANATION
Step 1: Increase in price = ₹50 - ₹40 = ₹10.
Step 2: Percentage increase = (Increase/Original Price) × 100 = (10/40) × 100 = 25%.

Therefore, option C is correct.

Test
Q.398 Easy Percentage Discount and Marked Price
A shirt marked at ₹800 is sold at a discount of 15%. What is the selling price?
A ₹680
B ₹720
C ₹760
D ₹740
Correct Answer:  A. ₹680
EXPLANATION
Step 1: Discount = 15% of ₹800 = 0.15 × 800 = ₹120.
Step 2: Selling Price = Marked Price - Discount = 800 - 120 = ₹680.

Therefore, option A is correct.

Test
Q.399 Easy Compound Interest
A sum of money doubles itself at 10% per annum compound interest. In how many years will it double?
A 7.2 years
B 7.5 years
C 8 years
D 6.5 years
Correct Answer:  A. 7.2 years
EXPLANATION
Step 1: Use formula 2P = P(1.10)^n where 2P is the doubled amount.
Step 2: Divide by P to get 2 = (1.10)^n.
Step 3: Taking log: n = log(2)/log(1.10) = 0.301/0.0414 ≈ 7.2 years.
Test
Q.400 Easy Compound Interest
Raj invested ₹12,000 at 8% per annum compound interest. What will be the amount after 2 years?
A ₹13,996.80
B ₹13,872.00
C ₹14,112.00
D ₹13,920.00
Correct Answer:  A. ₹13,996.80
EXPLANATION
Step 1: Use compound interest formula A = P(1 + r/100)^n.
Step 2: A = 12000(1 + 8/100)^2 = 12000(1.08)^2 = 12000 × 1.1664 = 13,996.80.
Step 3: The amount after 2 years is ₹13,996.80.
Test
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