Home Subjects Electronics (ECE) Analog Circuits

Electronics (ECE)
Analog Circuits

Analog/digital electronics, communication

47 Q 4 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 31–40 of 47
Topics in Electronics (ECE)
Q.31 Medium Analog Circuits
In a Wein bridge oscillator, the frequency of oscillation is given by f = 1/(2πRC). At what condition does oscillation start?
A When gain = 1/3
B When gain ≥ 3
C When gain = 2
D When phase shift = 180°
Correct Answer:  B. When gain ≥ 3
EXPLANATION

Wein bridge oscillator requires loop gain ≥ 3 to overcome the attenuation of the bridge network (which has 1/3 attenuation at oscillation frequency).

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Q.32 Medium Analog Circuits
The Miller effect in a Common Emitter amplifier results in:
A Increase in input capacitance
B Decrease in bandwidth
C Both A and B
D Increase in gain
Correct Answer:  C. Both A and B
EXPLANATION

Miller effect causes effective input capacitance to increase by factor (1 + |Av|), reducing input impedance and bandwidth. This limits high-frequency response.

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Q.33 Medium Analog Circuits
In an RC phase shift oscillator, how many RC sections are typically used to achieve 180° phase shift?
A One
B Two
C Three
D Four
Correct Answer:  C. Three
EXPLANATION

Three RC sections are used, each providing 60° phase shift. Total = 3 × 60° = 180°, which combined with 180° from inverting amp gives 360° (0°) for sustained oscillation.

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Q.34 Medium Analog Circuits
A Class B amplifier has two transistors operating in push-pull configuration. What is the maximum theoretical efficiency?
A 50%
B 78.5%
C 88.5%
D 95%
Correct Answer:  B. 78.5%
EXPLANATION

Class B has maximum efficiency of π/4 ≈ 78.5%. Each transistor conducts 180° of the signal cycle, eliminating idle current waste compared to Class A.

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Q.35 Medium Analog Circuits
For the oscillator to sustain oscillations, the loop gain must satisfy which condition (assuming phase shift is 360° or 0°)?
A Loop gain = 0
B Loop gain ≥ 1
C Loop gain < 0.5
D Loop gain = 0.5
Correct Answer:  B. Loop gain ≥ 1
EXPLANATION

Barkhausen criterion requires loop gain ≥ 1 (or |A×β| ≥ 1) for sustained oscillations; less than 1 causes damping, more than 1 causes amplitude growth until saturation.

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Q.36 Medium Analog Circuits
Which configuration provides the highest input impedance and lowest output impedance among op-amp circuits?
A Inverting amplifier
B Non-inverting amplifier
C Voltage follower (unity gain buffer)
D Summing amplifier
Correct Answer:  C. Voltage follower (unity gain buffer)
EXPLANATION

Voltage follower has Zin ≈ infinity (determined by op-amp input impedance) and Zout ≈ 0, making it ideal for impedance transformation.

Test
Q.37 Medium Analog Circuits
A BJT amplifier exhibits thermal runaway due to increased leakage current. Which design modification can best prevent this phenomenon?
A Increase the base bias resistor value
B Use a voltage divider bias network with low impedance
C Reduce the collector supply voltage
D Increase the emitter bypass capacitor
Correct Answer:  B. Use a voltage divider bias network with low impedance
EXPLANATION

Voltage divider bias with low impedance provides stiff bias independent of transistor parameters, preventing thermal runaway by maintaining stable base voltage despite temperature changes.

Test
Q.38 Medium Analog Circuits
In a saturated BJT transistor used as a switch, the voltage drop VCE(sat) is typically
A 0 V (ideally)
B 0.1 - 0.3 V
C 0.7 V
D 5 V
Correct Answer:  B. 0.1 - 0.3 V
EXPLANATION

In saturation, VCE(sat) ≈ 0.1-0.3 V for silicon BJT (not zero due to residual resistance). VBE(on) ≈ 0.7V in saturation. This is used in switching applications.

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Q.39 Medium Analog Circuits
The gain-bandwidth product (GBP) of an op-amp is approximately constant. For a 741 op-amp with GBP ≈ 1 MHz, the open-loop gain at 100 kHz is approximately
A 10 V/V
B 100 V/V
C 1000 V/V
D 10000 V/V
Correct Answer:  A. 10 V/V
EXPLANATION

GBP = Aol × f. For 741: 1 MHz = Aol × 100 kHz, therefore Aol = 1 MHz / 100 kHz = 10 V/V. GBP is approximately constant over frequency.

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Q.40 Medium Analog Circuits
In a Colpitts oscillator, the frequency of oscillation is determined by
A Only inductance L
B Only capacitance values
C L and the series combination of capacitors C1 and C2
D L and parallel combination of C1 and C2
Correct Answer:  C. L and the series combination of capacitors C1 and C2
EXPLANATION

Colpitts oscillator frequency f = 1/(2π√(L·Ceq)) where Ceq = (C1·C2)/(C1+C2). Voltage divider is formed by C1 and C2 for feedback.

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