Home Subjects Electronics (ECE) Electronic Devices

Electronics (ECE)
Electronic Devices

Analog/digital electronics, communication

41 Q 4 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 21–30 of 41
Topics in Electronics (ECE)
Q.21 Medium Electronic Devices
In a BJT common-emitter amplifier, if input impedance needs to be increased, the preferred biasing technique is:
A Fixed base bias
B Collector feedback bias
C Voltage divider bias with emitter resistor
D Emitter bias alone
Correct Answer:  C. Voltage divider bias with emitter resistor
EXPLANATION

Voltage divider bias with emitter resistor provides stability and increases input impedance through negative feedback from emitter resistor.

Test
Q.22 Medium Electronic Devices
The breakdown mechanism in a Zener diode at low doping concentrations is primarily:
A Avalanche multiplication
B Zener tunneling
C Impact ionization
D Thermal runaway
Correct Answer:  A. Avalanche multiplication
EXPLANATION

Low doping leads to wide depletion region favoring avalanche breakdown (impact ionization) rather than direct Zener tunneling.

Test
Q.23 Medium Electronic Devices
A Schottky diode compared to a pn-junction diode has:
A Higher forward voltage drop
B Lower forward voltage drop and faster switching
C Slower recovery time
D Higher reverse saturation current and lower leakage
Correct Answer:  B. Lower forward voltage drop and faster switching
EXPLANATION

Schottky diodes have forward voltage ~0.3-0.4V (vs 0.7V for Si) and fast switching due to no stored charge in depletion region.

Test
Q.24 Medium Electronic Devices
In a Zener diode regulation circuit, increasing load current causes:
A Zener current to increase
B Zener current to decrease
C Output voltage to increase
D Series resistor voltage to decrease
Correct Answer:  B. Zener current to decrease
EXPLANATION

As load current increases, less current flows through the Zener diode to maintain constant output voltage, so Zener current decreases.

Test
Q.25 Medium Electronic Devices
Which statement correctly describes the Early effect in BJTs?
A Base current increases without input signal change
B Early voltage depends on doping concentration and geometry
C It causes constant gain independent of VCE
D Collector current decreases as VCE decreases
Correct Answer:  B. Early voltage depends on doping concentration and geometry
EXPLANATION

Early voltage (VA) is a parameter that depends on the base width modulation effect with collector-base reverse bias voltage.

Test
Q.26 Medium Electronic Devices
A MOSFET operating in triode (linear) region exhibits:
A VDS > VGS - VTh
B VDS < VGS - VTh
C VDS = VGS - VTh
D VDS is independent of VGS
Correct Answer:  B. VDS < VGS - VTh
EXPLANATION

In triode region, the condition VDS < VGS - VTh allows the channel to conduct with resistance proportional to VDS.

Test
Q.27 Medium Electronic Devices
In a thyristor (SCR), the holding current (IH) is important because:
A It determines maximum forward current
B It is the minimum current required to maintain conduction after gate pulse is removed
C It controls the forward voltage drop
D It increases with temperature
Correct Answer:  B. It is the minimum current required to maintain conduction after gate pulse is removed
EXPLANATION

Holding current IH: minimum anode current to sustain regenerative action (latching); if IA < IH, device reverts to blocking state.

Test
Q.28 Medium Electronic Devices
In a photodiode, the photocurrent is proportional to:
A Applied reverse bias voltage
B Incident light intensity and quantum efficiency
C Forward bias current
D Operating temperature
Correct Answer:  B. Incident light intensity and quantum efficiency
EXPLANATION

Photodiode: Iph = η·q·Φ where η is quantum efficiency and Φ is incident photon flux; reverse bias increases depletion width for carrier collection.

Test
Q.29 Medium Electronic Devices
Channel length modulation in MOSFETs causes:
A Reduced saturation current
B Finite output impedance Rds ≈ VA/ID
C Increased threshold voltage
D Zero Early voltage effect
Correct Answer:  B. Finite output impedance Rds ≈ VA/ID
EXPLANATION

CLM: as VDS increases, pinch-off point moves toward source, reducing effective channel length; output resistance Rds = VA/ID = λ⁻¹.

Test
Q.30 Medium Electronic Devices
The gain-bandwidth product (GBP) of a BJT is approximately equal to:
A Current gain × operating frequency
B Transconductance / gate capacitance
C fT (transit frequency) where hFE·fβ = constant
D Collector current / base-emitter voltage
Correct Answer:  C. fT (transit frequency) where hFE·fβ = constant
EXPLANATION

GBW ≈ fT; BJT current gain drops with frequency as β·f ≈ constant, where fT is extrapolated cutoff frequency (~1GHz for silicon BJTs).

Test
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