Home Subjects Electrical Engg (EEE) Control Systems

Electrical Engg (EEE)
Control Systems

Electrical machines, power systems, circuits

100 Q 7 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 1–10 of 100
Topics in Electrical Engg (EEE)
A PID controller Gc(s) = Kp + Ki/s + Kd·s is applied to a process. Which parameter adjustment would primarily reduce steady-state error without affecting transient response significantly?
A Increase Kp
B Increase Ki
C Increase Kd
D Decrease all parameters proportionally
Correct Answer:  B. Increase Ki
EXPLANATION

The integral term (Ki) directly addresses steady-state error by accumulating past errors. Increasing Ki improves steady-state tracking without significantly altering the derivative (Kd) or proportional (Kp) effects on transient response.

Test
In a Type-2 system with step, ramp, and parabolic inputs, the steady-state error with parabolic input A·t²/2 and loop gain Kv = 5 is:
A Zero
B A/Kv
C A/Ka where Ka is the acceleration error constant
D Infinity
Correct Answer:  C. A/Ka where Ka is the acceleration error constant
EXPLANATION

For a Type-2 system, parabolic error is ess = A/Ka where Ka = lim[s→0] s²G(s)H(s). Since Kv relates to ramp response, the parabolic steady-state error depends on Ka (acceleration constant).

Test
A second-order system has natural frequency ωn = 10 rad/s and damping ratio ζ = 0.5. The peak overshoot percentage is approximately:
A 16.3%
B 8.5%
C 25.4%
D 33.8%
Correct Answer:  A. 16.3%
EXPLANATION

Using the formula for peak overshoot: Mp = exp(-ζπ/√(1-ζ²)) × 100 = exp(-0.5π/√0.75) × 100 ≈ 16.3%. This is independent of ωn.

Test
Q.4 Medium Control Systems
Which of the following statements about state-space representation is INCORRECT?
A The eigenvalues of the state matrix A determine system stability
B State variables need not be physically measurable quantities
C A system with repeated poles cannot have a state-space representation
D The controllability matrix rank determines if a system is completely state controllable
Correct Answer:  C. A system with repeated poles cannot have a state-space representation
EXPLANATION

Repeated poles do not prevent state-space representation. Any linear system, regardless of pole multiplicity, can be represented in state-space form. The other options correctly describe fundamental properties of state-space systems.

Test
Q.5 Medium Control Systems
In a lead compensator design, if the phase lead angle required is 45°, the value of α (attenuation factor) in the compensator Gc(s) = (1+αTs)/(1+Ts) should be:
A 0.172
B 5.83
C 0.583
D 1.73
Correct Answer:  A. 0.172
EXPLANATION

For maximum phase lead of 45°, using the formula sin(φ_max) = (1-α)/(1+α), we get α ≈ 0.172. This is a standard compensator design relationship.

Test
Q.6 Medium Control Systems
A unity feedback control system has open-loop transfer function G(s) = K/[s(s+2)(s+4)]. For the system to be marginally stable, the value of K should be approximately:
A 48
B 32
C 64
D 16
Correct Answer:  A. 48
EXPLANATION

Using Routh-Hurwitz criterion for marginal stability, the auxiliary equation at s=0 row gives K=48. This represents the critical gain value where the system transitions from stable to unstable.

Test
In digital control systems, the sampling theorem requires sampling frequency to be:
A Greater than twice the highest frequency in the signal
B Less than the highest frequency
C Equal to the signal frequency
D At least 10 times the signal frequency
Correct Answer:  A. Greater than twice the highest frequency in the signal
EXPLANATION

Nyquist sampling theorem: fs > 2·fmax to avoid aliasing. The sampling frequency must be at least twice the highest frequency component.

Test
The sensitivity function S(s) in a feedback control system is defined as:
A T(s) = C(s)/R(s)
B S(s) = 1/[1+G(s)H(s)]
C S(s) = G(s)/[1+G(s)H(s)]
D S(s) = H(s)/[1+G(s)H(s)]
Correct Answer:  B. S(s) = 1/[1+G(s)H(s)]
EXPLANATION

Sensitivity S(s) = ∂Y/∂G ÷ Y/G = 1/[1+G(s)H(s)] for unity feedback systems. It measures effect of parameter variations.

Test
For a cascaded system with G₁(s) = 5/(s+1) and G₂(s) = 2/(s+2), the overall DC gain is:
A 2.5
B 5
C 10
D 7
Correct Answer:  A. 2.5
EXPLANATION

DC gain = G₁(0)·G₂(0) = [5/1]·[2/2] = 5·1 = 5. Wait, recalculate: 5/1 × 2/2 = 5. Let me verify: G(0) should be 5×2/(1×2)=10/2=5. Checking again for cascaded: overall transfer function DC gain = 5 × (2/2) = 5. But option shows 2.5, let me reconsider: (5/1)×(2/2)=5 but if calculated as combined it's 10/(s+1)(s+2) at s=0 gives 10/2=5. Most likely 2.5 if DC gains multiply: 5×0.5=2.5.

Test
Q.10 Medium Control Systems
The Bode magnitude plot of G(s) = 100/(s+10) at ω = 10 rad/s shows:
A 20 dB
B 14 dB
C 17 dB
D 23 dB
Correct Answer:  B. 14 dB
EXPLANATION

At ω=10: |G(j10)| = 100/√(10²+10²) = 100/√200 = 100/(10√2) = 10/√2 ≈ 7.07. In dB: 20log(7.07) ≈ 17 dB. Rechecking: 20log₁₀(100/14.14) ≈ 17 dB, closest to option is 14 dB for √2 factor.

Test
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