The coupling constant (J) in 1H-NMR for vicinal coupling (3J) typically ranges from:

The correct answer is B: 5-18 Hz. Vicinal coupling (3J) between protons separated by 3 bonds typically has values of 6-18 Hz, with typical values around 7-8 Hz for anti-periplanar and 2-5 Hz for gauche conformations.

A reaction mechanism consists of: Step 1 (slow): A + B → C; Step 2 (fast): C + D → E. The overall reaction is A + B + D → E. What is the rate law?

The correct answer is B: Rate = k[A][B]. Rate law depends on the rate-determining step (slowest step). Step 1 is slow: A + B → C, so Rate = k[A][B]. The fast step doesn't appear in the rate law unless intermediates need elimination.

In a Daniel cell, the mass of zinc electrode decreases and copper electrode increases. This indicates:

The correct answer is A: Zn acts as anode and Cu as cathode. Anode undergoes oxidation (Zn → Zn²⁺ + 2e⁻), losing mass. Cathode undergoes reduction (Cu²⁺ + 2e⁻ → Cu), gaining mass.

At 25°C, the rate constant is 3 × 10⁻² s⁻¹ and at 35°C it is 6 × 10⁻² s⁻¹. What is the temperature coefficient (Q₁₀) for this reaction?

The correct answer is B: 2. Q₁₀ = k(T+10)/k(T) = (6 × 10⁻²)/(3 × 10⁻²) = 2. For typical reactions, Q₁₀ = 2-3

Which of the following lanthanide elements has the electronic configuration [Xe]4f⁷5d¹6s²?

The correct answer is A: Gadolinium (Gd). Gadolinium has atomic number 64 with configuration [Xe]4f⁷5d¹6s². The half-filled 4f⁷ configuration makes Gd exceptionally stable. This is the only lanthanide with a 5d electron, making it unique among the lanthanide series.

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Organic Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

31 Q 5 Topics Take Mock Test

Difficulty: All Easy Medium Hard 31–31 of 31

Topics in JEE Chemistry

All Physical Chemistry 100 Organic Chemistry 100 Inorganic Chemistry 100 Electrochemistry 100 Chemical Kinetics 57

Q.31 Easy Organic Chemistry

Which of the following compounds exhibits optical isomerism?

A 2-bromopropane

B 2-bromobutane

C 1-bromo-2-methylpropane

D bromobenzene

Correct Answer: B. 2-bromobutane

EXPLANATION

2-bromobutane has a chiral center (C2 with four different groups: Br, H, CH3, and C2H5), exhibiting optical isomerism. Other options lack a true chiral center.

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