Govt. Exams
Entrance Exams
From D > E and E ≥ A: D > E ≥ A. From C > D: C > D > E ≥ A. From B ≥ C and A < B: B ≥ C > D > E ≥ A, but A < B. Final: D < E < A < C < B.
We cannot conclusively determine the relationship between roses and cheap items because we don't know if red roses exist or if all red flowers are non-cheap.
Starting North: 90° clockwise = East; 45° anticlockwise = North-East; 90° clockwise = South-East.
From the chain: P ≥ Q > R > S and T ≤ Q. Since Q > R > S and P ≥ Q, we get P ≥ Q > R > S, so P > S is definitely true.
All students are learners (Students ⊆ Learners). Some learners are teachers means not all learners are teachers. Therefore, some learners are not teachers. This is definitely true.
P at position 1. Q is 2 clockwise: position 3. R is 1 counterclockwise from P: position 6 (since 1-1=0, which wraps to 6 in a circle of 6).
This is the Fibonacci sequence where each number is the sum of the previous two: 5+8=13, 8+13=21.
Square table with 2 people per side = 8 people total. X and Y are opposite. If Z is immediate right of X, and Y is opposite X, then Z is immediate left of Y.
Premise 1: All birds are animals. Premise 2: Some animals are not mammals. This tells us some animals (not specified which) are not mammals. Birds could be the non-mammals or could all be mammals. We cannot definitively conclude about birds and mammals. The answer is 'Cannot be determined'.
M is father of N. N is mother of P (P is daughter of N). P is mother of O (O is son of P). Therefore, O is grandson of M.
