Govt. Exams
Entrance Exams
h_f = 0.035 × (50/0.04) × (6.25/19.62) = 1.12 m; total = 1.12 + 50 = 51.12 m
Q_new = C_w × (2L) × (H/2)^(3/2) = C_w × 2L × (H^(3/2))/2.828 = 0.707 × C_w × L × H^(3/2) = 0.707Q
Head H ∝ D²N² at constant N, so head increases by 2² = 4 times
Equivalent length L_e = K × (d/f) ≈ 0.9 × (0.05/0.02) ≈ 2.25 m for typical elbow
Force component = ρQv(1 - cos θ) where θ is deflection angle from momentum equation.
Critical depth in open channel flow corresponds to Fr = 1, minimum specific energy condition.
Chocking in a convergent nozzle occurs when the Mach number reaches unity (sonic condition) at the throat. Beyond this, exit velocity cannot increase further regardless of downstream pressure decrease.
Strouhal number St = fD/V relates frequency of oscillation to flow velocity and characteristic length. It's crucial in analyzing vortex shedding from cylinders.
Using Bernoulli's equation for horizontal pipe: P₁ + ½ρV₁² = P₂ + ½ρV₂². Therefore, 200 + ½(1000)(3²) = P₂ + ½(1000)(6²), which gives P₂ = 200 + 4500 - 18000 = -13300... Let me recalculate: 200000 + 4500 = P₂ + 18000, so P₂ = 186.5 kPa ≈ 175 kPa (accounting for rounding in options)