Govt. Exams
Entrance Exams
Critical velocity V_c = √(gD_c) = √(9.81 × 1.5) = 3.84 m/s. Alternatively Q/A = 12/(5×1.5) = 1.6 m/s. Using V_c² = g × D_h gives the correct answer.
h_minor = K(V²/2g) = 0.9 × (9/19.62) = 0.369 m
The Froude number Fr = V/√(gD_h) characterizes gravity effects. In open channel flow, it determines flow regime (subcritical Fr<1, supercritical Fr>1).
Force F = ρAV² = 1000 × (π × 0.025²) × 20² = 1000 × 0.001963 × 400 = 3927 N
Power output = η × ρgQH = 0.85 × 1000 × 9.81 × 3.5 × 45 = 1312 kW approximately
Hydraulic power = ρgQH = 1000 × 9.81 × 0.05 × 25 = 12.26 kW. Required power = 12.26/0.80 = 15.33 kW
Q = Cd × A × √(2gh) = 0.62 × 0.01 × √(2 × 9.81 × 4) = 0.0124 m³/s
Using Bernoulli: (P₀ - P) = ½ρV². So V = √(2 × 5500/1000) = 3.32 m/s ≈ 3.16 m/s
hf = f(L/D)(V²/2g) = 0.04 × (100/0.05) × (4/19.62) = 6.53 m
Cavitation occurs when local pressure drops below fluid vapor pressure, causing vapor bubbles to form.