A force of 50 N is applied at 60° to the horizontal surface. The vertical component of the force is:

The correct answer is B: 43.3 N. Vertical component = F sin(60°) = 50 × (√3/2) = 50 × 0.866 = 43.3 N

The coefficient of performance (COP) of a refrigerator is 5. The work input required to remove 500 J of heat is:

The correct answer is A: 100 J. COP = Q_removed/W_input, so W = Q/COP = 500/5 = 100 J

A particle undergoes circular motion with radius 2 m and completes one revolution in 4 seconds. What is its centripetal acceleration?

The correct answer is A: π² m/s². Angular velocity ω = 2π/4 = π/2 rad/s. Centripetal acceleration = ω²r = (π/2)² × 2 = π² m/s²

The coefficient of performance (COP) of a refrigerator is 5. If 100 J of work is done on it, how much heat is removed from the cold reservoir?

The correct answer is B: 500 J. COP = Q_cold/W. Therefore, Q_cold = COP × W = 5 × 100 = 500 J

When a substance changes phase from solid to liquid at its melting point at constant temperature and pressure, which is true?

The correct answer is B: ΔG is zero. At equilibrium phase transition (melting point), ΔG = 0. This is the condition for phase equilibrium at constant T and P.

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NEET Physics
Electrostatics & Magnetism

Physics questions for NEET UG — Mechanics, Thermodynamics, Optics, Modern Physics.

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NEET Physics
Electrostatics & Magnetism