Home Subjects NEET Zoology Genetics & Evolution

NEET Zoology
Genetics & Evolution

Zoology questions for NEET UG — Animal Kingdom, Human Physiology, Genetics, Evolution.

50 Q 6 Topics Take Mock Test
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Topics in NEET Zoology
Which genetic concept explains why children of the same parents can have different traits despite inheriting genes from both?
A Dominance and recessiveness
B Genetic recombination and segregation
C Mutation and natural selection
D Gene expression and epigenetics
Correct Answer:  B. Genetic recombination and segregation
EXPLANATION

Segregation of alleles and recombination during meiosis create genetic variation in offspring, leading to phenotypic differences.

Test
Antibiotic resistance in bacteria develops rapidly due to:
A Bacteria intentionally mutating to survive
B Natural selection acting on pre-existing genetic variation
C Antibiotics causing specific mutations
D Horizontal gene transfer preventing natural selection
Correct Answer:  B. Natural selection acting on pre-existing genetic variation
EXPLANATION

Antibiotic resistance emerges through natural selection. Resistant bacteria survive antibiotic treatment and reproduce, increasing resistance frequency in the population.

Test
A dihybrid cross (AaBb × AaBb) is performed. What is the probability of getting the recessive phenotype for both traits?
A 1/16
B 3/16
C 9/16
D 7/16
Correct Answer:  A. 1/16
EXPLANATION

For AaBb × AaBb: probability of aa = 1/4, probability of bb = 1/4. Combined: 1/4 × 1/4 = 1/16

Test
In Darwin's theory of natural selection, 'variation' is important because it:
A Allows organisms to adapt to changing environments
B Ensures all organisms are identical
C Prevents evolution from occurring
D Makes organisms weaker over time
Correct Answer:  A. Allows organisms to adapt to changing environments
EXPLANATION

Variation provides the raw material for natural selection. Without variation, there would be no differential reproductive success.

Test
A person is heterozygous for cystic fibrosis (Ff). Their partner is homozygous normal (FF). What is the probability of having an affected child?
A 0%
B 25%
C 50%
D 75%
Correct Answer:  A. 0%
EXPLANATION

Cross: Ff × FF produces FF and Ff offspring. All are phenotypically normal. Probability of affected (ff) child = 0%

Test
Which of the following best represents anagenesis in evolution?
A Splitting of one species into two species
B Gradual transformation of one species into another over time
C Extinction of a species due to environmental change
D Rapid speciation through geographic isolation
Correct Answer:  B. Gradual transformation of one species into another over time
EXPLANATION

Anagenesis refers to phyletic evolution or linear evolution where one species gradually transforms into another without branching.

Test
A tall plant (genotype unknown) is crossed with a dwarf plant. All offspring are tall. What is the most likely genotype of the tall parent?
A Homozygous dominant (TT)
B Heterozygous (Tt)
C Homozygous recessive (tt)
D Cannot be determined
Correct Answer:  A. Homozygous dominant (TT)
EXPLANATION

All offspring being tall when crossed with dwarf (tt) indicates the tall parent is TT. If it were Tt, approximately half offspring would be dwarf.

Test
In a population at Hardy-Weinberg equilibrium, if the frequency of recessive allele (q) = 0.3, what is the frequency of heterozygous individuals?
A 0.42
B 0.09
C 0.49
D 0.91
Correct Answer:  A. 0.42
EXPLANATION

If q = 0.3, then p = 0.7. Heterozygous frequency = 2pq = 2(0.7)(0.3) = 0.42

Test
A gene has four alleles in a population. If three alleles have frequencies of 0.4, 0.3, and 0.2, what is the frequency of the fourth allele?
A 0.1
B 0.5
C 0.9
D 0.6
Correct Answer:  A. 0.1
EXPLANATION

According to Hardy-Weinberg principle, total allele frequencies must equal 1. Therefore, 1 - (0.4 + 0.3 + 0.2) = 0.1

Test
In ABO blood group genetics, if both parents have AB blood group, what blood groups are IMPOSSIBLE in their children?
A O group
B A group
C B group
D Both A and B groups
Correct Answer:  A. O group
EXPLANATION

AB parents (IAIB × IAIB) produce IAIA, IAIB, and IBIB only. O group (ii) requires two recessive alleles, which neither parent possesses.

Test
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