Govt. Exams
Entrance Exams
Let B = 100. Then A = 140 (40% more). C = 70 (30% less). Difference = 140-70 = 70. Percentage = (70/70)×100 = 100%
My mother's daughter = I (the woman). So 'This man's mother is I (the woman)'. Therefore, the man in the photograph is the woman's son.
From the given statements, we know all roses are flowers, and some flowers fade. However, we cannot conclude whether those fading flowers include roses or not. The fading flowers could be a different subset.
Each letter is shifted forward by 1 position in the alphabet. M→N, O→P, R→S, N→O, I→J, N→O, G→H. Applying the same rule to EVENING: E→F, V→W, E→F, N→O, I→J, N→O, G→H = FWFOJOH
From transitive property: X > Y > Z > W, therefore X > W is definitely true.
First letter increases (A→B→C→D→E), second letter decreases (Z→Y→X→W→V). Answer is EV.
Hour hand moves 30° per hour (360°/12). 120°/30° = 4 hours. 3:00 + 4 hours = 7:00. But checking: 120° from 3 = 5:00 position.
S is mother of R, Q is sister of R, so Q is daughter of S. P is daughter of Q, so P is granddaughter of S.
Pattern: 2(1²×2), 8(2²×2), 18(3²×2), 32(4²×2), 50(5²×2), 72(6²×2). Each term = n²×2.
Using set theory: Total = Cricket + Football - Both. 50 = 30 + 25 - Both. Both = 55 - 50 = 5.
