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Chemical Engineering

Process design, thermodynamics, reactions

133 Q 5 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 91–100 of 133
Topics in Chemical Engineering
Q.91 Easy Heat Transfer
In a parallel flow heat exchanger, the temperature approach is minimum at which end?
A Hot fluid inlet
B Cold fluid outlet
C Hot fluid outlet
D Depends on mass flow rates
Correct Answer:  C. Hot fluid outlet
EXPLANATION

In parallel flow, both fluids flow in the same direction. The smallest temperature difference (approach) occurs at the outlet end where the hot fluid has cooled and cold fluid has heated.

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Q.92 Easy Heat Transfer
What is the SI unit of thermal conductivity?
A W/(m·K)
B J/(s·m·K)
C kcal/(h·m·°C)
D Both A and B
Correct Answer:  D. Both A and B
EXPLANATION

Thermal conductivity is expressed as W/(m·K) in SI units, which is equivalent to J/(s·m·K) since 1 W = 1 J/s.

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Q.93 Easy Heat Transfer
A flat-plate solar collector has a black absorber plate maintained at 80°C. The ambient temperature is 20°C and the heat loss coefficient (overall U value including radiation and convection) is 8 W/(m²·K). For a collector area of 4 m², what is the heat loss rate to the surroundings?
A 960 W
B 1440 W
C 1920 W
D 2880 W
Correct Answer:  C. 1920 W
EXPLANATION

Q_loss = U × A × ΔT = 8 × 4 × (80-20) = 8 × 4 × 60 = 1920 W. The overall U value already accounts for both convective and radiative losses.

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Q.94 Easy Heat Transfer
In radiation heat transfer, the Stefan-Boltzmann constant σ has a value of 5.67 × 10⁻⁸ W/(m²·K⁴). A black body at 500 K radiates heat. If the temperature is doubled to 1000 K, by what factor does the radiated heat increase?
A 2 times
B 4 times
C 8 times
D 16 times
Correct Answer:  D. 16 times
EXPLANATION

According to Stefan-Boltzmann law, Q = σAT⁴. When T increases from 500 K to 1000 K, the factor becomes (1000/500)⁴ = 2⁴ = 16 times. Radiation is highly temperature-dependent due to the fourth-power relationship.

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Q.95 Easy Heat Transfer
The Nusselt number (Nu) relationship for laminar flow in a circular pipe is given by Nu = 3.66. What does this value represent?
A The ratio of convective to conductive heat transfer at the pipe entrance
B The thermally developed laminar flow condition with constant wall temperature
C The average Nusselt number for fully developed laminar flow with constant heat flux
D The entrance region Nusselt number for transitional flow
Correct Answer:  B. The thermally developed laminar flow condition with constant wall temperature
EXPLANATION

The value of 3.66 is the fully developed Nusselt number for laminar flow in circular pipes under constant wall temperature (T_s constant) boundary condition, representing the thermal development region.

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Q.96 Easy Heat Transfer
In a shell-and-tube heat exchanger, what is the primary advantage of using baffles?
A To increase turbulence and improve heat transfer coefficient on the shell side
B To reduce the pressure drop across the exchanger
C To decrease the surface area required for heat transfer
D To eliminate fouling on heat transfer surfaces
Correct Answer:  A. To increase turbulence and improve heat transfer coefficient on the shell side
EXPLANATION

Baffles in shell-and-tube heat exchangers create turbulence by forcing the fluid to flow in a cross-flow pattern, significantly increasing the convective heat transfer coefficient on the shell side, which enhances overall heat transfer effectiveness.

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Q.97 Easy Heat Transfer
Which of the following materials would be most suitable for a heat sink application requiring high thermal conductivity and low cost?
A Pure copper (k = 400 W/m·K)
B Aluminum alloy (k = 160 W/m·K)
C Stainless steel (k = 16 W/m·K)
D Carbon fiber composite (k = 100 W/m·K)
Correct Answer:  B. Aluminum alloy (k = 160 W/m·K)
EXPLANATION

Aluminum alloys offer an excellent balance of thermal conductivity (160 W/m·K, sufficient for most applications), cost-effectiveness, light weight, corrosion resistance, and ease of machining. While copper has higher conductivity, aluminum's cost-benefit ratio is superior for heat sink applications.

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Q.98 Easy Heat Transfer
A horizontal cylindrical pipe carries hot water at 80°C through ambient air at 20°C. The convective heat transfer coefficient is 25 W/m²·K and pipe diameter is 50 mm. Calculate heat loss per unit length if the pipe is not insulated.
A 47.1 W/m
B 78.5 W/m
C 94.2 W/m
D 156.3 W/m
Correct Answer:  A. 47.1 W/m
EXPLANATION

Q/L = h·π·d·ΔT = 25 × π × 0.05 × (80-20) = 25 × π × 0.05 × 60 = 235.6/5 ≈ 47.1 W/m

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Q.99 Easy Heat Transfer
In the context of thermal radiation, the Stefan-Boltzmann constant has a value of:
A 5.67 × 10⁻⁸ W/m²·K⁴
B 6.67 × 10⁻¹¹ m³/kg·s²
C 1.38 × 10⁻²³ J/K
D 8.314 J/mol·K
Correct Answer:  A. 5.67 × 10⁻⁸ W/m²·K⁴
EXPLANATION

The Stefan-Boltzmann constant σ = 5.67 × 10⁻⁸ W/m²·K⁴ is used in radiation heat transfer calculations (Q = σAε(T⁴)). Other options are physical constants used in different domains.

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Q.100 Easy Heat Transfer
Which of the following dimensionless numbers is used to predict the transition from laminar to turbulent flow in forced convection?
A Grashof number (Gr)
B Reynolds number (Re)
C Rayleigh number (Ra)
D Fourier number (Fo)
Correct Answer:  B. Reynolds number (Re)
EXPLANATION

Reynolds number determines the flow regime in forced convection. Re < 2300 indicates laminar flow, Re > 4000 indicates turbulent flow. Grashof and Rayleigh are used for natural convection, while Fourier number is for transient conduction.

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