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Chemical Engineering

Process design, thermodynamics, reactions

117 Q 5 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 11–20 of 117
Topics in Chemical Engineering
Q.11 Hard Thermodynamics
When CO₂ gas at 1 atm is cooled below the sublimation temperature (~195 K), it directly converts to dry ice without passing through liquid phase. This phenomenon is explained by:
A Triple point pressure of CO₂ (5.1 atm) being higher than 1 atm
B Critical temperature of CO₂ being lower than room temperature
C High sublimation enthalpy
D Negative slope of solid-liquid equilibrium line
Correct Answer:  A. Triple point pressure of CO₂ (5.1 atm) being higher than 1 atm
EXPLANATION

CO₂ triple point is at 5.1 atm and 216.6 K. At 1 atm, cooling solid CO₂ cannot reach liquid phase because pressure is insufficient. Sublimation occurs directly solid→gas.

Test
Q.12 Hard Thermodynamics
The osmotic pressure of a dilute solution is given by van't Hoff equation: π = iMRT. What does 'i' represent?
A Van't Hoff factor (colligative property modifier)
B Number of moles of solute per liter
C Ideality correction factor
D Activity coefficient of solute
Correct Answer:  A. Van't Hoff factor (colligative property modifier)
EXPLANATION

The van't Hoff factor i accounts for ionic dissociation in solution. For non-electrolytes i ≈ 1; for electrolytes i > 1 (e.g., NaCl: i ≈ 2). Essential for colligative property calculations.

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Q.13 Hard Thermodynamics
The Clausius-Clapeyron equation relates vapor pressure to temperature. Which assumption is NOT required for its derivation?
A Equilibrium between liquid and vapor phases
B Constant enthalpy of vaporization
C Vapor behaves as an ideal gas
D The system is open
Correct Answer:  D. The system is open
EXPLANATION

Clausius-Clapeyron requires phase equilibrium, constant ΔH_vap, ideal gas approximation, but works for closed systems

Test
Q.14 Hard Thermodynamics
For a non-ideal binary mixture, the activity coefficient (γᵢ) deviates from unity when:
A The mixture is dilute
B Intermolecular interactions are significant
C The system is at very low pressure
D The components are structurally similar
Correct Answer:  B. Intermolecular interactions are significant
EXPLANATION

Activity coefficients account for non-ideal behavior due to intermolecular forces and molecular size differences

Test
Q.15 Hard Thermodynamics
The Maxwell relation derived from Gibbs free energy (G = H - TS) is:
A (∂S/∂P)_T = (∂V/∂T)_P
B (∂V/∂T)_P = -(∂S/∂P)_T
C (∂P/∂T)_V = (∂S/∂V)_T
D (∂T/∂V)_S = (∂P/∂S)_V
Correct Answer:  B. (∂V/∂T)_P = -(∂S/∂P)_T
EXPLANATION

From dG = -SdT + VdP, the Maxwell relation is: (∂V/∂T)_P = -(∂S/∂P)_T

Test
Q.16 Hard Thermodynamics
In a throttling process (Joule-Thomson expansion), for an ideal gas:
A Temperature increases
B Temperature decreases
C Temperature remains constant
D Entropy decreases
Correct Answer:  C. Temperature remains constant
EXPLANATION

For ideal gas, enthalpy H depends only on temperature. In throttling (isenthalpic process), H = constant, so T = constant for ideal gas. For real gases, T may change based on Joule-Thomson coefficient.

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Q.17 Hard Thermodynamics
The partial molar Gibbs energy at infinite dilution gives the chemical potential μ. For a component in ideal solution:
A μᵢ = μᵢ⁰ + RT ln(xᵢ)
B μᵢ = μᵢ⁰ + RT ln(aᵢ)
C μᵢ = μᵢ⁰ - RT ln(xᵢ)
D μᵢ = μᵢ⁰ + RT ln(γᵢxᵢ)
Correct Answer:  A. μᵢ = μᵢ⁰ + RT ln(xᵢ)
EXPLANATION

For ideal solutions, the chemical potential is μᵢ = μᵢ⁰ + RT ln(xᵢ), where xᵢ is the mole fraction. For non-ideal solutions, the activity aᵢ = γᵢxᵢ is used.

Test
Q.18 Hard Thermodynamics
The Maxwell relation that can be derived from Gibbs free energy is:
A (∂S/∂P)ₜ = (∂V/∂T)ₚ
B (∂S/∂P)ₜ = -(∂V/∂T)ₚ
C (∂T/∂P)ₛ = (∂V/∂S)ₚ
D (∂P/∂T)ₛ = (∂S/∂V)ₜ
Correct Answer:  B. (∂S/∂P)ₜ = -(∂V/∂T)ₚ
EXPLANATION

From dG = -SdT + VdP, the Maxwell relation is (∂S/∂P)ₜ = -(∂V/∂T)ₚ. This relates entropy-pressure change to volume-temperature change.

Test
For homogeneous gas-phase reaction in batch reactor, if pressure increases at constant volume, what happens to reaction rate for 2A → Products?
A Decreases
B Remains unchanged
C Increases by factor of 4
D Increases by factor of 2
Correct Answer:  C. Increases by factor of 4
EXPLANATION

Pressure increase increases concentration proportionally; for 2nd order rate = kC_A², quadrupling concentration increases rate 16-fold; doubling pressure quadruples rate.

Test
In a recycle reactor with recycle ratio R, what is the volume reduction factor compared to PFR for equivalent conversion?
A (1+R)/R
B R/(1+R)
C (1+R)/(1+R²)
D 1 + 1/R
Correct Answer:  A. (1+R)/R
EXPLANATION

Recycle reduces required volume by factor (1+R)/R compared to PFR for same conversion and residence time.

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