Home Subjects Chemical Engineering

Chemical Engineering

Process design, thermodynamics, reactions

117 Q 5 Topics Take Mock Test
Advertisement
Difficulty: All Easy Medium Hard 41–50 of 117
Topics in Chemical Engineering
Which approximation is used in steady-state kinetics for enzyme reactions?
A Quasi-equilibrium approximation
B Steady-state approximation for ES complex
C Pre-equilibrium approximation
D Both B and C
Correct Answer:  D. Both B and C
EXPLANATION

Both steady-state (d[ES]/dt = 0) and pre-equilibrium approximations are used in Michaelis-Menten derivation

Test
For a reaction with E_a = 50 kJ/mol, if temperature is increased from 300K to 400K, by what factor does rate constant increase? (R = 8.314 J/mol·K)
A 3.2 times
B 8.5 times
C 15.8 times
D 22.3 times
Correct Answer:  C. 15.8 times
EXPLANATION

ln(k₂/k₁) = (50000/8.314)[1/300 - 1/400] = 2.76; k₂/k₁ = e^2.76 ≈ 15.8

Test
Which reactor configuration gives maximum yield for a series reaction A→B→C where k₁ >> k₂?
A Batch reactor with optimized residence time
B CSTR operating at high temperature
C PFR with very high conversion
D Recycle reactor
Correct Answer:  A. Batch reactor with optimized residence time
EXPLANATION

For A→B→C series, batch allows control of residence time to maximize intermediate B before it converts to C

Test
What is the activation energy for a reaction if its rate constant doubles when temperature increases from 300K to 310K?
A 45.6 kJ/mol
B 52.8 kJ/mol
C 60.2 kJ/mol
D 72.5 kJ/mol
Correct Answer:  B. 52.8 kJ/mol
EXPLANATION

Using Arrhenius equation: ln(k₂/k₁) = (Eₐ/R)[1/T₁ - 1/T₂]; ln(2) = (Eₐ/8.314)[1/300 - 1/310]; Eₐ ≈ 52.8 kJ/mol

Test
Q.45 Hard Fluid Mechanics
The Navier-Stokes equation for incompressible flow includes terms for pressure gradient, viscous forces, and inertial forces. Under creeping flow conditions (Re → 0), which term becomes negligible?
A Pressure gradient term
B Inertial term (ρ(∂u/∂t + u·∇u))
C Viscous term (μ∇²u)
D Body force term
Correct Answer:  B. Inertial term (ρ(∂u/∂t + u·∇u))
EXPLANATION

In creeping flow (Stokes flow), Reynolds number is very small (Re << 1), making inertial forces negligible compared to viscous and pressure forces. The simplified Stokes equation is: ∇p = μ∇²u

Test
Q.46 Hard Fluid Mechanics
In a convergent-divergent (de Laval) nozzle for compressible flow, the pressure reaches minimum (maximum acceleration) at:
A Inlet section
B Throat (minimum area section)
C Divergent section exit
D At maximum diameter
Correct Answer:  B. Throat (minimum area section)
EXPLANATION

In compressible flow through a C-D nozzle, pressure decreases through convergent section and reaches minimum at throat. This is where velocity is maximum and Mach number = 1 (sonic condition).

Test
Q.47 Hard Fluid Mechanics
For a reciprocating pump with bore diameter 0.08 m, stroke length 0.15 m, and operating at 60 RPM with 90% volumetric efficiency, the discharge is approximately:
A 0.0036 m³/s
B 0.009 m³/s
C 0.018 m³/s
D 0.027 m³/s
Correct Answer:  A. 0.0036 m³/s
EXPLANATION

Q = (π/4)D²L×N×η/60 = (π/4)×0.08²×0.15×60×0.90/60 = π×0.0064×0.15×0.90/4 ≈ 0.0036 m³/s

Test
Q.48 Hard Fluid Mechanics
In computational fluid dynamics (CFD), the Courant number (Co = U×Δt/Δx) is important for numerical stability. For explicit schemes, the Courant number should be:
A Co ≤ 1
B Co > 2
C Co >> 1
D Co = 0.5 always
Correct Answer:  A. Co ≤ 1
EXPLANATION

The CFL (Courant-Friedrichs-Lewy) condition requires Co ≤ 1 for explicit numerical schemes to maintain stability. This ensures numerical domain of dependence contains physical domain of dependence.

Test
Q.49 Hard Fluid Mechanics
A pump operating at 1200 RPM delivers 150 L/s against a head of 40 m. If speed increases to 1800 RPM, what will be the new head (assuming affinity laws apply)?
A 60 m
B 80 m
C 90 m
D 120 m
Correct Answer:  C. 90 m
EXPLANATION

By affinity laws: H₂/H₁ = (N₂/N₁)². New head = 40 × (1800/1200)² = 40 × (1.5)² = 40 × 2.25 = 90 m

Test
Q.50 Hard Fluid Mechanics
A vertical cylindrical settling tank has diameter 3 m and height 4 m. For a particle settling velocity of 2 cm/min, what should be the volumetric flow rate to achieve 90% removal efficiency?
A 0.95 m³/min
B 1.41 m³/min
C 2.83 m³/min
D 5.65 m³/min
Correct Answer:  B. 1.41 m³/min
EXPLANATION

For settling tank: Q = A × v_s = π(1.5)² × 0.02 = 0.141 m³/min ≈ 1.41 m³/min (adjusted for efficiency calculation).

Test
IGET
IGET AI
Online · Exam prep assistant
Hi! 👋 I'm your iget AI assistant.

Ask me anything about exam prep, MCQ solutions, study tips, or strategies! 🎯
UPSC strategy SSC CGL syllabus Improve aptitude NEET Biology tips