A first-order low-pass filter has transfer function H(s) = ωc/(s + ωc). At what frequency (in terms of ωc) does the magnitude response drop to 1/√2 of its DC value?
Aω = ωc/2
Bω = ωc
Cω = 2ωc
Dω = ωc/√2
Correct Answer:
B. ω = ωc
EXPLANATION
At DC (ω=0): |H(j0)| = 1. At ω = ωc: |H(jωc)| = ωc/√(ωc² + ωc²) = 1/√2. This is the -3dB cutoff frequency, a fundamental property of first-order filters.
The Z-transform of a discrete-time signal is X(z) = z/(z-0.5) with ROC |z| > 0.5. The corresponding time-domain signal is:
Ax[n] = 0.5^n × u[n]
Bx[n] = δ[n] + 0.5^n × u[n]
Cx[n] = 0.5^(n-1) × u[n-1]
Dx[n] = δ[n-1] × 0.5^n
Correct Answer:
A. x[n] = 0.5^n × u[n]
EXPLANATION
Using partial fractions or standard Z-transform tables: X(z) = z/(z-0.5) corresponds to x[n] = 0.5^n × u[n] where u[n] is the unit step function. The ROC |z| > 0.5 confirms a causal right-sided sequence.
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