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JEE Chemistry
Chemical Kinetics

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

26 Q 5 Topics Take Mock Test
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Difficulty: All Easy Medium Hard 21–26 of 26
Topics in JEE Chemistry
Q.21 Medium Chemical Kinetics
At 300 K, a reaction has a half-life of 10 minutes. At 310 K, the half-life becomes 5 minutes. What is the approximate value of temperature coefficient (assuming RRT ≈ 2)?
A 1.5
B 2.0
C 2.5
D 3.0
Correct Answer:  B. 2.0
EXPLANATION

For a first-order reaction, if half-life decreases from 10 to 5 minutes (becomes half) with a 10 K increase, this indicates the reaction rate doubles per 10 K, giving a temperature coefficient of 2.

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Q.22 Medium Chemical Kinetics
For the reaction A → B, the integrated rate law for zero-order kinetics is:
A [A] = [A]₀ - kt
B ln[A] = ln[A]₀ - kt
C 1/[A] = 1/[A]₀ + kt
D [A]² = [A]₀² - kt
Correct Answer:  A. [A] = [A]₀ - kt
EXPLANATION

For zero-order reaction: d[A]/dt = -k, integrating gives [A] = [A]₀ - kt, which is a linear equation.

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Q.23 Medium Chemical Kinetics
According to Arrhenius equation, k = Ae^(-Eₐ/RT), a catalyst increases reaction rate by:
A Increasing the frequency factor A
B Decreasing the activation energy Eₐ
C Increasing the temperature T
D Decreasing the pre-exponential factor
Correct Answer:  B. Decreasing the activation energy Eₐ
EXPLANATION

A catalyst provides an alternative reaction pathway with lower activation energy, thus increasing the rate constant k without affecting A or T.

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Q.24 Medium Chemical Kinetics
Which of the following graphs represents a first-order reaction?
A Plot of [A] vs t is linear
B Plot of ln[A] vs t is linear
C Plot of 1/[A] vs t is linear
D Plot of [A]² vs t is linear
Correct Answer:  B. Plot of ln[A] vs t is linear
EXPLANATION

For a first-order reaction, ln[A] = ln[A]₀ - kt, so a plot of ln[A] vs t gives a straight line with slope -k.

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Q.25 Medium Chemical Kinetics
The mechanism of a reaction is: Step 1: A + B → C (slow), Step 2: C + D → E + F (fast). What is the overall reaction and the rate law?
A A + B + D → E + F; rate = k[A][B]
B A + B + D → E + F; rate = k[C][D]
C A + B + C + D → E + F; rate = k[A][B][D]
D A + B → E + F; rate = k[A]²[B]
Correct Answer:  A. A + B + D → E + F; rate = k[A][B]
EXPLANATION

The overall reaction is obtained by adding all steps and canceling intermediates: A + B + D → E + F. Rate law is determined by the slow step: rate = k[A][B]

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Q.26 Medium Chemical Kinetics
For a first-order reaction, if the initial concentration is [A]₀ = 0.5 M and after 30 seconds it becomes 0.25 M, what is the rate constant?
A 0.0231 s⁻¹
B 0.0115 s⁻¹
C 0.0462 s⁻¹
D 0.0577 s⁻¹
Correct Answer:  A. 0.0231 s⁻¹
EXPLANATION

Using ln([A]₀/[A]ₜ) = kt, ln(0.5/0.25) = k × 30, ln(2) = k × 30, k = 0.693/30 = 0.0231 s⁻¹

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