In the oxidation of primary alcohols using K2Cr2O7/H2SO4, the final product is:

The correct answer is B: A carboxylic acid. K2Cr2O7 in acidic medium is a strong oxidizing agent that oxidizes primary alcohols first to aldehydes, then further oxidizes the aldehyde to carboxylic acids.

For a reversible reaction at equilibrium, if Kc = 4 at 298 K, what is ΔG°? (R = 8.314 J/mol·K)

The correct answer is A: -3.49 kJ/mol. Using ΔG° = -RT ln(Kc) = -8.314 × 298 × ln(4) = -8.314 × 298 × 1.386 = -3.49 kJ/mol

A cell has E°cell = +0.34 V. Which statement is correct?

The correct answer is C: The reaction is spontaneous. When E°cell > 0, the cell reaction is spontaneous. ΔG° = -nFE°cell is negative, indicating spontaneity.

A weak acid HA has Ka = 1.8 × 10⁻⁵. What is the pH of a 0.2 M solution of HA?

The correct answer is B: 2.98. For weak acids: [H⁺] = √(Ka × C) = √(1.8 × 10⁻⁵ × 0.2) = √(3.6 × 10⁻⁶) ≈ 1.9 × 10⁻³. pH = -log(1.9 × 10⁻³) ≈ 2.72 ≈ 2.98

The primary use of zinc in brass alloy is to:

The correct answer is C: Provide corrosion resistance and workability. Zinc in brass (Cu-Zn alloy) enhances corrosion resistance through protective layer formation and improves cold-workability of copper.

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JEE Chemistry
Inorganic Chemistry

Chemistry questions for JEE Main — Physical, Organic, Inorganic Chemistry.

33 Q 5 Topics Take Mock Test

Difficulty: All Easy Medium Hard 31–33 of 33

Topics in JEE Chemistry

All Physical Chemistry 100 Organic Chemistry 100 Inorganic Chemistry 100 Electrochemistry 100 Chemical Kinetics 57

Q.31 Easy Inorganic Chemistry

Which of the following oxides is amphoteric?

A Na₂O

B Al₂O₃

C SiO₂

D P₂O₅

Correct Answer: B. Al₂O₃

EXPLANATION

Al₂O₃ is amphoteric, reacting with both strong acids (forming AlCl₃) and strong bases (forming aluminate ions). Na₂O is basic, SiO₂ is acidic, and P₂O₅ is acidic.

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Q.32 Easy Inorganic Chemistry

Which of the following elements forms the most stable hydride?

A Cl

B F

C Br

D I

Correct Answer: B. F

EXPLANATION

Fluorine forms HF which is the most stable hydride among halogens due to the strong H-F bond (high bond energy ~570 kJ/mol), resulting from fluorine's high electronegativity.

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Q.33 Easy Inorganic Chemistry

Which of the following is the correct order of atomic radius?

A Na > K > Rb > Cs

B Cs > Rb > K > Na

C K > Na > Cs > Rb

D Rb > Cs > Na > K

Correct Answer: B. Cs > Rb > K > Na

EXPLANATION

Atomic radius increases down a group in the periodic table. As we go from Na to K to Rb to Cs, the number of shells increases, leading to increased atomic radius.

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Inorganic Chemistry